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adelina 88 [10]
3 years ago
6

All of the following expressions have the same value, when x = -2 and y = 4, except _____.

Mathematics
2 answers:
Mrrafil [7]3 years ago
6 0
I think the answer is c
irinina [24]3 years ago
4 0

Answer:

C

Step-by-step explanation:

When plugged in it is -4(-2)² which equals -16 while the others equal 16

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What is 265,200 rounded to the nearest hundred thousand
MaRussiya [10]

265,000

Hope this helps!

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3 years ago
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I need help with 25.
noname [10]

Sum of linear pair of angles = 180°

so

<EFG + <GFH = 180°

2n + 21 + 4n + 15 = 180°

6n + 36 = 180°

6n = 144

n = 24

<EFG = 2(24) + 21 = 69°

<GFH = 4n + 15 = 4(24) + 15 = 111°

6 0
3 years ago
(-1)3 exponet is 3 help me please i dont want to fail
Natali5045456 [20]

Answer:

-1

i do not remember how to solve this but i just answered a question that had this problem in it on my algebra test and that is the right answer

8 0
3 years ago
The height of a building is 943 feet which is about 481 feet higher than another building. What is the height of the second buil
pshichka [43]

Answer: 462


Step-by-step explanation:

943-481

Answer=462

6 0
3 years ago
Find, correct to four decimal places, the length of the curve of intersection of the cylinder 16x2 + y2 = 16 and the plane x + y
Yuri [45]

Let the curve C be the intersection of the cylinder  



16x^2+y^2=16



and the plane



x+y+z=1



The projection of C on to the x-y plane is the ellipse



16x^2+y^2=16



To see clearly that this is an ellipse, le us divide through by 16, to get



\frac{x^2}{1}+ \frac{y^2}{16}=1



or  



\frac{x^2}{1^2}+ \frac{y^2}{4^2}=1,



We can write the following parametric equations,



x=cos(t), y=4sin(t)



for  



0\le t \le 2\pi



Since C lies on the plane,



x+y+z=1



it must satisfy its equation.



Let us make z the subject first,  



z=1-x-y



This implies that,



z=1-sin(t)-4cos(t)



We can now write the vector equation of C, to obtain,



r(t)=(cos(t),4sin(t),1-cos(t)-4sin(t))



The length of the curve of the intersection of the cylinder and the plane is now given by,



\int\limits^{2\pi}_0 {|r'(t)|} \, dt



But  



r'(t)=(-sin(t),4cos(t),sin(t)-4cos(t))



|r'(t)|=\sqrt{(-sin(t))^2+(4cos(t))^2+(sin(t)-4cos(t))}



\int\limits^{2\pi}_0 {\sqrt{2sin^2(t)+32cos(t)-8sin(t)cos(t)} }\, dt=24.08778184



Therefore the length of the curve of the intersection  intersection of the cylinder and the plane is 24.0878 units correct to four decimal places.

6 0
3 years ago
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