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3 years ago

Find the value of x in the triangle shown below.(not a test just need help with khan academy)

Mathematics

2 answers:

Delicious77 [7]3 years ago

5 0

Using angle sum property

$\\ \sf\longmapsto x+44+29=180$

$\\ \sf\longmapsto x+63=180$

$\\ \sf\longmapsto x=180-63$

$\\ \sf\longmapsto x=117°$

e-lub [12.9K]3 years ago

5 0

The angle sum property of a triangle:

The total measure of the three angles of a triangle is 180°

$\large\bf{\red{ \longrightarrow}} \: \tt \: x \: + \: 44 \degree \: + \: 29 \degree \: = \: 180 \degree$

$\large\bf{\red{ \longrightarrow}} \: \tt \: x \: + \: 73 \degree \: = \: 180 \degree$

$\large\bf{\red{ \longrightarrow}} \: \tt \: x \: = \: 180 \degree \: - \: 73 \degree \:$

$\large\bf{\red{ \longrightarrow}} \: \tt \: x \: = \: 107 \degree$

<h3>⇛ Value of x is 107°</h3>

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Hundred sixty thousand,five hundred eighty-two in expanded form

gulaghasi [49]

160,582 = 100,000 + 60,000 + 500 + 80 + 2

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6 0

3 years ago

What’s the equivalent to 12(3+m)

Anon25 [30]

Answer:

36+12m

Step-by-step explanation:

12 * 3 = 36

12 * m = 12m

Using the distributive property, the answer would be: 36+12m

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4 years ago

Right Triangle Trig.

d1i1m1o1n [39]

The values are vx = $\frac{14\sqrt{3} }{\sqrt{2} }$ , vw = $\frac{14\sqrt{3} }{\sqrt{2} }$ and m∠x = 45°, for the given right angle diagram.

Step-by-step explanation:

The given is,

Right angled triangle XVW,

XW = 14 $\sqrt{3}$

m∠V = 90°

m∠W = 45°

Step:1

Given diagram is right angle triangle,

Trigonometric ratios for right angle is,

$sin$ ∅ $=\frac{Opp}{Hyp}$ ............................(1)

$cos$ ∅ $= \frac{Adj}{Hyp}$ .........................(2)

$tan$ ∅ $= \frac{Opp}{Hyp}$ ..........................(3)

Step:2

For the value of VX,

$sin$ ∅ $=\frac{VX}{XW}$

From given,

∅ = 45°

XW = 14 $\sqrt{3}$

Above equation becomes,

$sin$ 45 $=\frac{VX}{14\sqrt{3} }$

Where, Sin 45 = $\frac{1}{\sqrt{2} }$ ,

$\frac{1}{\sqrt{2} } = \frac{VX}{14\sqrt{3} }$

$VX = \frac{14\sqrt{3} }{\sqrt{2} }$

Step:3

For the value of VW,

$cos$ ∅ $=\frac{VW}{XW}$

From given,

∅ = 45°

XW = 14 $\sqrt{3}$

Above equation becomes,

$cos$ 45 $=\frac{VW}{14\sqrt{3} }$

Where, cos 45 = $\frac{1}{\sqrt{2} }$ ,

$\frac{1}{\sqrt{2} } = \frac{VW}{14\sqrt{3} }$

$VW = \frac{14\sqrt{3} }{\sqrt{2} }$

Step:4

For the value m∠x = a,

$tan$ a $=\frac{VX}{VW}$

From given,

VX = $\frac{14\sqrt{3} }{\sqrt{2} }$

VW = $\frac{14\sqrt{3} }{\sqrt{2} }$

Above equation becomes,

$tan$ a $=\frac{\frac{14\sqrt{3} }{\sqrt{2} } } {\frac{14\sqrt{3} }{\sqrt{2} } }$

$tan$ a = 1

a = $tan^{-1}$ (1)

a = 45°

m∠x = a = 45°

Step:5

Check for solution,

m∠v = m∠w + m∠x

= 45° + 45°

90° = 90°

Result:

The values are vx = $\frac{14\sqrt{3} }{\sqrt{2} }$ , vw = $\frac{14\sqrt{3} }{\sqrt{2} }$ and m∠x = 45°, for the given right angle diagram.

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4 years ago

Solve the system of equations by elimination. Explain your reasoning or show your work.

saul85 [17]

9514 1404 393

Answer:

(x, y) = (5, 4)

Step-by-step explanation:

Subtracting the second equation from the first eliminates the x term.

(4x +6y) -(4x +2y) = (44) -(28)

4y = 16 . . . . simplify

y = 4

Using the second equation to find x, we have ...

4x +2(4) = 28

x + 2 = 7 . . . . . . divide by 4

x = 5 . . . . . . . . . subtract 2

The solution is (x, y) = (5, 4).

7 0

3 years ago

Roger is sixteen years old and eats granola bars. He attends P.R. Walker High School. In this example, is the independent variab

adelina 88 [10]

The example in that question, the age of Roger is the independent variable. This means that the variable left is <span>granola bars. This make it the dependent variable since it depends on the age of Roger.

The age does not depend on the amount of </span>granola bars eaten by Roger but the amount of <span>granola bars may depend with age of Roger.</span>

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3 years ago