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2 years ago

For the Parabola y = (x - 7)^2 – 3. the equation for the Line Of Symmetry is

Mathematics

2 answers:

8090 [49]2 years ago

7 0

Answer:

x+=(y)=x

Step-by-step explanation:

allochka39001 [22]2 years ago

7 0

Answer:

x = 7

Step-by-step explanation:

y = (x - 7)^2 – 3

This equation is in vertex form

y = a(x-h)^2 +k where (h,k) is the vertex. For a vertical parabola, the axis of symmetry is x=h

x = 7

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Trina has two brothers. one brother is 7 years older than trina and the other brother is 7 years younger than trina. the product

AlladinOne [14]

(a) 95 = (x+7)*(x-7)

(b) 95 = (x+7)*(x-7)
Expand the brackets:
95 = x² -7x + 7x -49 = x² - 49
Subtract x² from both sides:
95-x² = -49
Subtract 95 from both sides:
-x²=-49-95
-x²= -144
Divide both sides by -1 to get rid of the negative numbers:
-x²/-1=-144/-1
x²=144
Take the square root of 144:
x = ± squareroot of 144
x = 12 or -12
x = 12 because you cannot have a negative age so Trina is 12 years old.

7 0

3 years ago

Anyone Know This Answer ?

OverLord2011 [107]

I hope this helps you

M^2+R^2=W^2

M^2+16=25

M^2=9

7 0

3 years ago

Read 2 more answers

Geometry please help asap!

m_a_m_a [10]

Step-by-step explanation:

AB = 3

by similaritiy criterion

CE/ CB= ED/AB

4/6= 2/AB

AB = 3

plz mark my answer as brainlist plzzzz also vote me ..if you find it useful.

6 0

3 years ago

The following options are available for a car wash

Margaret [11]

Answer:

£576

(would really, reallly appreciate the brainliest)

Step-by-step explanation:

8 * 60 * 3/5 + 12 * 60 * 2/5

3 0

3 years ago

1 The prism-shaped roof has equilateral triangular bases. Use the model you created in question #1 to calculate the height of th

Diano4ka-milaya [45]

Answer:

Step-by-step explanation:

Step-by-step explanation: As shown in the attached figure, the prism-shaped roof has equilateral triangular bases, one of which is ΔABC. We need to create an equation that models the height of one of the roof's triangular bases in terms of its sides. Let ii be AD.

See the figure attached herewith, ΔABC forms an equilateral triangle, in which AD is the height. So, D will be the mid-point of BC and ∠ADB = ∠ADC = 90°.

Now, in ΔADB, we have

AD^2=AB^2-BD^2

AD^2=AB^2-(1/2AB^2)^2

AD=√3/4AB^2

we can find the height of any one of the roof's triangular bases.

2.1. Check picture 1. Let the one side of the triangle be a, drop one perpendicular, CD. Then triangle ADB is a right triangle, with hypothenuse a and one side equal to 1/2a. By the Pythagorean theorem, as shown in the picture, the height is √3/2a

2. if a=25 ft, then the height is √3/2a=√3/2*25=1.732/2*25=21.7(ft)

3. consider picture 2. Let the length of the roof be l feet.

one side of the prism (the roof) is a rectangle with dimensions a and l, so the area of one side is a*l

the lateral Area of the roof is 3a*l

the area of the equilateral surfaces is 2*(1/2*a*√3/2a)=√3/2a^2

so the total area of the roof is

4. The total area was the 2 triangular surfaces + the 3 equal lateral rectangular surfaces. Now instead of 3 lateral triangular surfaces, we have 2.

So the total area found previously will be decreased by al

5. so the area now is √3/2a^2 + 2al

6. now a=25 and l=2a=50

Area= √3/2a^2+2al=√3/2*25^2+2*25*50=25^2(√3/2+4)=625*4.866

=3041.3 (ft squared)

6 0

2 years ago