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2 years ago

For the Parabola y = (x - 7)^2 – 3. the equation for the Line Of Symmetry is

Mathematics

2 answers:

8090 [49]2 years ago

7 0

Answer:

x+=(y)=x

Step-by-step explanation:

allochka39001 [22]2 years ago

7 0

Answer:

x = 7

Step-by-step explanation:

y = (x - 7)^2 – 3

This equation is in vertex form

y = a(x-h)^2 +k where (h,k) is the vertex. For a vertical parabola, the axis of symmetry is x=h

x = 7

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consider the following set of equations: equation a: y = 2x 4 equation b: y = 3x 1 which of the following is a step that can be

loris [4]

Y = 2x + 4 and y = 3x + 1
Therefore, 2x + 4 = 3x + 1

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2 years ago

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A new soup recipe contains 33\%33%33, percent less sodium per serving than the old soup recipe. The old soup recipe contained xx

Mashcka [7]

Answer:

0.67x mg

Step-by-step explanation:

expression that could represent the amount of sodium per serving, in milligrams, in the new soup recipe

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3 years ago

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For the function y=3x2: (a) Find the average rate of change of y with respect to x over the interval [3,6]. (b) Find the instant

nirvana33 [79]

Answer:

The instantaneous rate of change of $y$ with respect to $x$ at the value $x = 3$ is 18.

Step-by-step explanation:

a) Geometrically speaking, the average rate of change of $y$ with respect to $x$ over the interval by definition of secant line:

$r = \frac{y(b) -y(a)}{b-a}$ (1)

Where:

$a$ , $b$ - Lower and upper bounds of the interval.

$y(a)$ , $y(b)$ - Function exaluated at lower and upper bounds of the interval.

If we know that $y = 3\cdot x^{2}$ , $a = 3$ and $b = 6$ , then the average rate of change of $y$ with respect to $x$ over the interval is:

$r = \frac{3\cdot (6)^{2}-3\cdot (3)^{2}}{6-3}$

$r = 27$

The average rate of change of $y$ with respect to $x$ over the interval $[3,6]$ is 27.

b) The instantaneous rate of change can be determined by the following definition:

$y' = \lim_{h \to 0}\frac{y(x+h)-y(x)}{h}$ (2)

Where:

$h$ - Change rate.

$y(x)$ , $y(x+h)$ - Function evaluated at $x$ and $x+h$ .

If we know that $x = 3$ and $y = 3\cdot x^{2}$ , then the instantaneous rate of change of $y$ with respect to $x$ is:

$y' = \lim_{h \to 0} \frac{3\cdot (x+h)^{2}-3\cdot x^{2}}{h}$

$y' = 3\cdot \lim_{h \to 0} \frac{(x+h)^{2}-x^{2}}{h}$

$y' = 3\cdot \lim_{h \to 0} \frac{2\cdot h\cdot x +h^{2}}{h}$

$y' = 6\cdot \lim_{h \to 0} x +3\cdot \lim_{h \to 0} h$

$y' = 6\cdot x$

$y' = 6\cdot (3)$

$y' = 18$

The instantaneous rate of change of $y$ with respect to $x$ at the value $x = 3$ is 18.

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2 years ago

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fgiga [73]

The answer is 2,800 or 2800

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3 years ago

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mojhsa [17]

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