Answer: 21
Step-by-step explanation:
Given : The scores on the midterm exam are normally distributed with

Let X be random variable that represents the score of the students.
z-score: 
For x=82

For x=90

Now, the probability of the students in the class receive a score between 82 and 90 ( by using standard normal distribution table ) :-

Now ,the number of students expected to receive a score between 82 and 90 are :-

Hence, 21 students are expected to receive a score between 82 and 90 .
Answer:
or 
Step-by-step explanation:
The given equation is

Let us treat this as a quadratic equation in
.
where 
The solution is given by the quadratic formula;

We substitute these values into the formula to obtain;





or 
or 
or 
or 
Answer:
Step-by-step explanation:
Let yesterday's price be x
Discount percentage = 36%
Sale price = $ 560
(100-36)% of x = 560
64 % *x = 560

Yesterday's price = $ 875