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lukranit [14]
3 years ago
6

Find h. 10 cm h h = ✓ [?] cm .... 6 cm ​

Mathematics
1 answer:
Evgesh-ka [11]3 years ago
8 0

Answer:

h²= G²- R²

h² = 10²-6²

h²= 100 - 36

h²= 64

h = √64

.............

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myrzilka [38]

Answer:

Step-by-step explanation:

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2 years ago
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"A solar hot-water heating system consists of a hot-water tank and a solar panel. The tank is well insulated and has a time cons
puteri [66]
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6 0
3 years ago
adiocarbon dating of blackened grains from the site of ancient Jericho provides a date of 1315 BC ± 13 years for the fall of the
Zigmanuir [339]

Answer:

\left(\frac{m(t)}{m_{o}} \right)_{min} \approx 0.659 and \left(\frac{m(t)}{m_{o}} \right)_{max} \approx 0.661

Step-by-step explanation:

The equation of the isotope decay is:

\frac{m(t)}{m_{o}} = e^{-\frac{t}{\tau} }

14-Carbon has a half-life of 5568 years, the time constant of the isotope is:

\tau = \frac{5568\,years}{\ln 2}

\tau \approx 8032.926\,years

The decay time is:

t = 1315\,years + 2007\,years \pm 13\,years (There is no a year 0 in chronology).

t = 3335 \pm 13\,years

Lastly, the relative amount is estimated by direct substitution:

\frac{m(t)}{m_{o}} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{\mp\frac{13\,years}{8032.926\,years} }

\left(\frac{m(t)}{m_{o}} \right)_{min} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{-\frac{13\,years}{8032.926\,years} }

\left(\frac{m(t)}{m_{o}} \right)_{min} \approx 0.659

\left(\frac{m(t)}{m_{o}} \right)_{max} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{\frac{13\,years}{8032.926\,years} }

\left(\frac{m(t)}{m_{o}} \right)_{max} \approx 0.661

4 0
2 years ago
12x+y=−4 y=2x+16 im really confused on how to do this, i need to find the solution
ololo11 [35]

Answer:

here

Step-by-step explanation:

5 0
2 years ago
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If you just write whatever just for the points i will report you.
Hoochie [10]

<u>Answer:</u>

Below!

<u>Step-by-step explanation:</u>

<u>The best way to answer this question is to read the statement carefully.</u>

  • => Five less than twice a number = 2x - 5
  • => Five times the sum of two numbers = 5(x + y)
  • => The difference of 5 and a number, squared = (5 - x)²

Hoped this helped.

BrainiacUser1357

5 0
2 years ago
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