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Marina86 [1]
4 years ago
6

Drag each expression to show whether it is equivalent to 54x + 18, 18(3x – 1), or (6 • 9x) + (6 • 1).  A.54x + 6 B(9 • 6x) – (9

• 2) C.54x – 18 18(3x + 1) D(6 • 9x) + (6 • 3) E.3(18x+2)
Mathematics
2 answers:
Firlakuza [10]4 years ago
5 0
Idk what the answer is try adding a picture.
kipiarov [429]4 years ago
5 0

Answer:

54x + 18 -> (6 • 9x) + (6 • 3) and 18(3x + 1)

18(3x – 1) -> (9 • 6x) – (9 • 2) and 54x – 18

(6 • 9x) + (6 • 1) -> 3(18x+2) and 54x + 6

Step-by-step explanation:

Rewrite expressions, so that, we can compare them.

Distributing 18(3x – 1) gives

18(3x – 1) = 18*3x - 18*1 = 54x - 18

In 18(3x + 1) and 3(18x+2) we can perform similarly

18*(3x + 1) = 18*3x + 18*1 = 54x + 18

3*(18x+2) = 3*18x + 3*2 = 54x + 6

Multiplying each term inside parenthesis in (6*9x) + (6*1) gives

(6*9x) + (6*1) = 54x + 6

In (9*6x) – (9*2) and (6*9x) + (6*3) we can perform similarly

(9*6x) – (9*2) = 54x - 18  

(6*9x) + (6*3) = 54x + 18

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