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2 years ago

In the figureAB = AD, BC = CDprove that ∠ABC = ∠ADC

Mathematics

2 answers:

butalik [34]2 years ago

6 0

AB = AD [Given]

BC = CD [Given]

AC = AC [Same line segment]

So, ΔABC ≅ ΔADC [By SSS congruence criteria]

So, ∠ABC = ∠ADC [CPCT (Corresponding parts of congruent triangles)]

Hence, proved.

Stolb23 [73]2 years ago

6 0

Answer:

I hope it will help U.

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Rus_ich [418]

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3 years ago

Harry's parrot is 11 years older than his cat.

Sav [38]

Answer:

The answer to your question is: P = 17 years

Step-by-step explanation:

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3 years ago

johns test grades in his science class are 82, 93, 75, and 89 what is his average? 1. (87.45) 2. (80.00) 3. (90.40) 4. (89.25) 5

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3 years ago

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3 years ago

Find the reference angle given: t= -5π/3.

Elina [12.6K]

Answer:

The reference angle is $\frac{\pi}{3}$

Step-by-step explanation:

The given angle is $t=-\frac{5\pi}{3}$

The reference angle is the acute angle, that a given angle makes with the x-axis.

First let us make a sketch of the given angle. <em>See diagram in attachment.</em>

Let $\theta$ be the reference angle of $t=-\frac{5\pi}{3}$

Then, from the diagram, we need to subtract $\theta$ from $-\frac{5\pi}{3}$ to get to $-2\pi$ .

We can therefore write the following equation and solve for $\theta$ .

$\Rightarrow -\frac{5\pi}{3}-\theta=-2\pi$

We group like terms to get,

$\Rightarrow -\theta=-2\pi +\frac{5\pi}{3}$

We collect LCM to get,

$\Rightarrow -\theta=\frac{-6\pi+5\pi}{3}$

We simplify to get,

$\Rightarrow -\theta=-\frac{\pi}{3}$

We divide through by $-1$

$\theta=\frac{\pi}{3}$ to get,

The correct answer is D.

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3 years ago

In the figureAB = AD, BC = CDprove that ∠ABC = ∠ADC​

In the figureAB = AD, BC = CDprove that ∠ABC = ∠ADC