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MrRa [10]
3 years ago
8

If the polygon is translated 3 units down and 4 units left, what will the coordinates of the new image be? Use prime notation in

expressing the new coordinates.
Mathematics
2 answers:
Anna [14]3 years ago
6 0
7 ... it's just 3+4 hope it helped!


lol


your welcome!
Fittoniya [83]3 years ago
3 0
4 units left : subtract 4 from each x coordinate 

3 units down : subtract 3 from each y coordinate 

that is how i remember it  
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Aubrey has $ -24 in her bank account. A store credits her account with a $10 refund. How much does she now have in the bank?
xz_007 [3.2K]
To get the answer you’ll need to add the $10 to the -24. After completing you’ll have the number -14. Glad to help :)
8 0
1 year ago
The area of a square is represented by the expression 16x^4y^8. What is the length of each side of this square
Leona [35]

Answer: 4x^2y^4

Step-by-step explanation:

Given

The area of the square is A=16x^4y^8

Suppose a is the side length of the square

The area of the square is given by

\Rightarrow A=(\text{side length})^2

So, we can write

\Rightarrow a^2=16x^4y^8\\\Rightarrow a=4x^2y^4

length of each side is 4x^2y^4

5 0
2 years ago
please help! a bike shop has 11 red bikes, 3 blue bikes, 4 orange bikes, and 12 silver bikes. for every 1 orange bike, there are
Tomtit [17]

Answer:

silver bikes...

4 0
3 years ago
(x+y+2)(y+1) <--- Please help,will mark brainly
kifflom [539]

Answer:

y^2+xy+x+3y+2

Step-by-step explanation:

first of all we have to multiplies the y in the second bracket for all numbers in the first bracket.

so we have:

xy+y^2+2y

now we have to do the same with 1

x+y+2

now we have to unite the two solutions

xy+y^2+2y+x+y+2

at least we have to added up the similar terms (that have the same literal part)

y^2+xy+x+3y+2

6 0
3 years ago
What intervals would you use to determine where<br> the function is positive and negative?
Igoryamba

Answer:

B.

Step-by-step explanation:

The function is positive when it is above the x-axis

The following x values are where the function has positive y coordinates:

(-2,0)

(4,inf)

The function is negative when it is below the x-axis

The following x values are where the function has negative y coordinates:

(-inf,-2)

(0,4)

So you should see all of these intervals listed in choice B

4 0
3 years ago
Read 2 more answers
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