Answer:
9√15·cis(19π/24)
Step-by-step explanation:
The magnitudes multiply and the angles add:
= ((3√3)(3√5))·cis(π/8 +2π/3)
= 9√15·cis(π(1/8 +2/3)) = 9√15·cis(π(3/24 +16/24))
= 9√15·cis(19π/24)
The area of Triangle ACE from the given diagram is; 150 sq.units
<h3>What is the area of the triangle?</h3>
We are given;
AB = 44
AC = 30
ME = 10
Now, to find the area of triangle ACE, we need to know the length KE where K is the midpoint of AC.
Now, since AD bisects angle BAC. This means that ∠KEA = ∠MEA.
By ASA Congruence Postulate, we can say that; ΔAEK ≅ AEM
Thus, we can say that KE = ME = 10
Formula for area of triangle is;
A = ¹/₂ * base * height
where;
base = AC = 30
Height = KE = 10
Thus;
A = ¹/₂ * 30 * 10
A = 150
Read more about area of the triangle at; brainly.com/question/17335144
It's not an equation because there's no answer to the problem.
