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san4es73 [151]
3 years ago
13

In triangle ABC, M is the midpoint of AB. Let D be the point on BC such that AD bisects angle BAC, and let the perpendicular bis

ector of AB intersect AD at E. If AB = 44, AC = 30, and ME = 10, then find the area of triangle ACE.
Help Please!
Mathematics
1 answer:
ziro4ka [17]3 years ago
7 0

The area of Triangle ACE from the given diagram is; 150 sq.units

<h3>What is the area of the triangle?</h3>

We are given;

AB = 44

AC = 30

ME = 10

Now, to find the area of triangle ACE, we need to know the length KE where K is the midpoint of AC.

Now, since AD bisects angle BAC. This means that ∠KEA = ∠MEA.

By ASA Congruence Postulate, we can say that; ΔAEK ≅ AEM

Thus, we can say that KE = ME = 10

Formula for area of triangle is;

A = ¹/₂ * base * height

where;

base = AC = 30

Height = KE = 10

Thus;

A =  ¹/₂ * 30 * 10

A = 150

Read more about area of the triangle at; brainly.com/question/17335144

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