Answer:
r = -12cos(θ)
Step-by-step explanation:
The usual translation can be used:
Putting these relationships into the formula, we have ...
(r·cos(θ) +6)² +(r·sin(θ))² = 36
r²·cos(θ)² +12r·cos(θ) +36 +r²·sin(θ)² = 36
r² +12r·cos(θ) = 0 . . . . subtract 36, use the trig identity cos²+sin²=1
r(r +12cos(θ)) = 0
This has two solutions for r:
r = 0 . . . . . . . . a point at the origin
r = -12cos(θ) . . . the circle of interest
Answer: I dont know
Step-by-step explanation: i need more information
Answer:
See answers below :)
Step-by-step explanation:
-2(2 - 5) + 10 + (-5) =
-2(-3) + 10 - 5 =
6 + 10 - 5 =
11
8 - 2(9 - 5)^2 - 1 =
8 - 2(4)^2 - 1 =
8 - 2(16) - 1 =
8 - 32 - 1 =
-25
Find the greatest common factor which is 9
9(9x^2-3x-2) and then factor the equation in the parenthesis
so the factored equation will be 9(3x+1)(3x-2)
I dont have paper with me but just solve 2(-2)^3+2 for the first one. The second one is -28 though
