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liq [111]
3 years ago
6

I need help ;^; please​

Mathematics
1 answer:
Andru [333]3 years ago
8 0

Answer:

\sqrt{3 {x}^{2} {y}^{3}  }  \times 2 \sqrt{72 {x}^{3} {y}^{4}  }  \\  = 2 \sqrt{3 {x}^{2} {y}^{3}  72 {x}^{3}  {y}^{4} }  \\  = 2 \times 6 \sqrt{6}  \times  \sqrt{ {x}^{5}  {y}^{7} }  \\ 12 \sqrt{6}  {x}^{2}  {y}^{3}  \sqrt{xy }  \\ 12 {x}^{2}  {y}^{3}  \sqrt{6xy}  \\ thank \: you

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Differentiating Exponential functions In Exercise,find the derivative of the function. See Example 2 and 3.
Lilit [14]

Answer:

5e⁵ˣ

Step-by-step explanation:

Use the implicit differentiation method

let 5x = a

da/dx = 5, da=5dx

y=eᵃ, dy/da=eᵃ

dy/dx=dy/da . da/dx

hence, dy/dx = 5e⁵ˣ

3 0
3 years ago
Order the following expressions by their values from least to greatest
svlad2 [7]
N-Q, N, Q-N

Explanation: N=-2/Q=1
Equations:
-2-1=-3(N-Q)
-2(N)
1- -2=3(Q-N)
4 0
3 years ago
Given the following geometric sequence, find the 12th term: {2, -4, 8, ...}.
jolli1 [7]

A geometric sequence has a common ratio.

The formula for the nth term is

\sf{a_n =ar^{n-1} }

where,

  • an = nth term of the sequence,
  • a = first term of the sequence and
  • r = common ratio

<u>Given</u> -

  • A geometric sequence 2, -4, 8, ...

<u>To find</u> -

  • the 12th term of the given geometric sequence

<u>Solution</u> -

A.T.Q, a = 2 and r = -2

\rightarrow\sf{a_{12} =2(-2)^{12-1} }

\rightarrow\sf{a_{12 }=2(-2)^{11} }

\rightarrow\sf{a_{12} =2×(-2048) }

\rightarrow\bf{a_{12 }=-4096 }

<u>Hence, the 12th term is -4096</u>.

5 0
2 years ago
What is a fraction equation that equals 4
ella [17]
16/4 could be reduced to 4
8 0
3 years ago
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6 ÷ 1/7 equals what?
Mazyrski [523]
42 because you have to multiply the reciprocal
5 0
4 years ago
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