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liq [111]
3 years ago
6

I need help ;^; please​

Mathematics
1 answer:
Andru [333]3 years ago
8 0

Answer:

\sqrt{3 {x}^{2} {y}^{3}  }  \times 2 \sqrt{72 {x}^{3} {y}^{4}  }  \\  = 2 \sqrt{3 {x}^{2} {y}^{3}  72 {x}^{3}  {y}^{4} }  \\  = 2 \times 6 \sqrt{6}  \times  \sqrt{ {x}^{5}  {y}^{7} }  \\ 12 \sqrt{6}  {x}^{2}  {y}^{3}  \sqrt{xy }  \\ 12 {x}^{2}  {y}^{3}  \sqrt{6xy}  \\ thank \: you

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