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777dan777 [17]
3 years ago
6

A. Determine if a given set ie a well-defined or not.

Mathematics
2 answers:
Natali [406]3 years ago
7 0

Answer:

Step-by-step explanation:

1. yes

2. No

3. No

4. Yes

5. I have no idea about this one, but I think its not a well defined set

yanalaym [24]3 years ago
4 0
^ for 5 its well defined. according to g00gle
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I need help really quick please
Lisa [10]
The answer would be 1/2
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3 years ago
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Find the values of x and y. Show your work.
san4es73 [151]
Use proportions:

(7x-4)/31 = (4y+8)/24 = (y+2)/6

Multiply:

6*(7x-4) = 31*(y+2)---> 42x-24 = 31y+62 ---> 11y = 86, y = 86/11

I don;t like that is looks 'ugly', instead of sth like y = 88/11=8. I think 86/11 is the answer. Check the math! :)


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3 years ago
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Two triangles can be formed with the given information. Use the Law of Sines to solve the triangles. B = 46°, a = 12, b = 11
andreyandreev [35.5K]
*Hint: The Law of Sines is Sin A/a = Sin B/b = Sin C/c

In order to solve this equation, you will have to use this equation:

A= sin^(-1)[a sinB/b]
A= sin^ (-1) [12 (sin 46°) / 11]
A = sin^ (-1) [8.632077604/11]
A = sin ^(-1) [0.7847343276]
A = 51.69611349

Therefore, Sine A would be about 52°
6 0
4 years ago
Subtract-a^2-5ab+3ab^2 from 3a^2-2ab+3b2
sergejj [24]

The correct answer is 4a^2 + 3ab

In order to find this, we can write the equation out as described and then follow the order of operations.

3a^2 - 2ab + 3b^2 - (-a^2 - 5ab + 3b^2) ----> Distribute the negative

3a^2 - 2ab + 3b^2 + a^2 + 5ab - 3b^2 ----> Combine like terms

4a^2 + 3ab

5 0
3 years ago
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Please help!! Write in simplest radical form: √7/8 Show how you figured it out
12345 [234]

Given expression: \sqrt{\frac{7}{8}}.

\mathrm{Apply\:radical\:rule\:}\sqrt[n]{\frac{a}{b}}=\frac{\sqrt[n]{a}}{\sqrt[n]{b}}

=\frac{\sqrt{7}}{\sqrt{8}}

\sqrt{8}=\sqrt{2^2\cdot \:2}=2\sqrt{2}

\frac{\sqrt{7}}{\sqrt{8}} =\frac{\sqrt{7}}{2\sqrt{2}}

\mathrm{Rationalize\:}\frac{\sqrt{7}}{2\sqrt{2}}

\mathrm{Multiply\:by\:the\:conjugate}\:\frac{\sqrt{2}}{\sqrt{2}}

=\frac{\sqrt{7}\sqrt{2}}{2\sqrt{2}\sqrt{2}}

=\frac{\sqrt{14}}{4}

=\frac{\sqrt{14}}{4}.

3 0
4 years ago
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