Question

Subtract-a^2-5ab+3ab^2 from 3a^2-2ab+3b2

Answer 1

Answer: $-4a^2+3ab^2-3ab-3b^2$

Step-by-step explanation:

$\left(-a^2-5ab+3ab^2\right)-\left(3a^2-2ab+3b^2\right)$

$=-a^2-5ab+3ab^2-\left(3a^2-2ab+3b^2\right)$

$=-a^2-5ab+3ab^2-3a^2+2ab-3b^2$

$=-4a^2+3ab^2-3ab-3b^2$

Answer 2

The correct answer is 4a^2 + 3ab

In order to find this, we can write the equation out as described and then follow the order of operations.

3a^2 - 2ab + 3b^2 - (-a^2 - 5ab + 3b^2) ----> Distribute the negative

3a^2 - 2ab + 3b^2 + a^2 + 5ab - 3b^2 ----> Combine like terms

4a^2 + 3ab