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2 years ago

My Christmas present to you

Mathematics

2 answers:

Mashcka [7]2 years ago

8 0

Answer:

Step-by-step explanation:

if you need help let me know

pantera1 [17]2 years ago

6 0

Thanksss. you’re a real one lol

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Please Help ill give brainliest!!!! Help ASAP

liq [111]

Answer:

Camille's puppy becuase it gains about half a pound per week

Step-by-step explanation:

3 0

2 years ago

A salesperson gets a 3% commission on the sale of a copy machine. What is his commission on a copy machine that costs $4,950.00?

kondor19780726 [428]

4,950×3=1650
1650÷100=16.5
his commission is $16.5

7 0

3 years ago

What is the slope of a linear function that passes between (2, 7) and (5, 12)?

Grace [21]

The formula of slope,

→ (y2 - y1)/(x2 - x1)

Then the slope will be,

→ m = (12 - 7)/(5 - 2)

→ [ m = 5/3 ]

Hence, thy slope is 5/3.

4 0

11 months ago

Use Stokes' Theorem to evaluate C F · dr F(x, y, z) = xyi + yzj + zxk, C is the boundary of the part of the paraboloid z = 1 − x

Serggg [28]

I assume $C$ has counterclockwise orientation when viewed from above.

By Stokes' theorem,

$\displaystyle\int_C\vec F\cdot\mathrm d\vec r=\iint_S(\nabla\times\vec F)\cdot\mathrm d\vec S$

so we first compute the curl:

$\vec F(x,y,z)=xy\,\vec\imath+yz\,\vec\jmath+xz\,\vec k$

$\implies\nabla\times\vec F(x,y,z)=-y\,\vec\imath-z\,\vec\jmath-x\,\vec k$

Then parameterize $S$ by

$\vec r(u,v)=\cos u\sin v\,\vec\imath+\sin u\sin v\,\vec\jmath+\cos^2v\,\vec k$

where the $z$ -component is obtained from

$1-(\cos u\sin v)^2-(\sin u\sin v)^2=1-\sin^2v=\cos^2v$

with $0\le u\le\dfrac\pi2$ and $0\le v\le\dfrac\pi2$ .

Take the normal vector to $S$ to be

$\vec r_v\times\vec r_u=2\cos u\cos v\sin^2v\,\vec\imath+\sin u\sin v\sin(2v)\,\vec\jmath+\cos v\sin v\,\vec k$

Then the line integral is equal in value to the surface integral,

$\displaystyle\iint_S(\nabla\times\vec F)\cdot\mathrm d\vec S$

$=\displaystyle\int_0^{\pi/2}\int_0^{\pi/2}(-\sin u\sin v\,\vec\imath-\cos^2v\,\vec\jmath-\cos u\sin v\,\vec k)\cdot(\vec r_v\times\vec r_u)\,\mathrm du\,\mathrm dv$

$=\displaystyle-\int_0^{\pi/2}\int_0^{\pi/2}\cos v\sin^2v(\cos u+2\cos^2v\sin u+\sin(2u)\sin v)\,\mathrm du\,\mathrm dv=\boxed{-\frac{17}{20}}$

6 0

3 years ago

Evaluate7.2÷0.38.(Round to the hundredth place as needed.)

polet [3.4K]

Answer:

18.95

Step-by-step explanation:

18.94736842 rounded to its nearest hundredth will be 18.95

6 0

3 years ago

My Christmas present to you​

My Christmas present to you