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2 years ago

A train is traveling at a constant speed and goes 7.5 kilometers in 6 minutes. At that rate:

Mathematics

2 answers:

Orlov [11]2 years ago

8 0

For distance in 1 minute, divide the distance for 6 minutes by 6 minutes:

7.5 km / 6 minutes = 1.25 km per minute.

For 100 minutes, multiply distance per minute by total minutes:

1.25 km per minute x 100 minutes = 125 km

nlexa [21]2 years ago

8 0

Answer:

1.25 km in 1 minute

125 km in 100 minutes

Step-by-step explanation:

Find its speed in km/min by dividing the km by number of minutes:

7.5/6

= 1.25

So, the train goes 1.25 km in 1 minute.

Using this speed, find how far it goes in 100 minutes, by multiplying the speed by 100:

1.25(100)

= 125

So, in 100 minutes, the train goes 125 km.

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2 years ago

Alonzo and Miguel scored a total of 54 points in a basketball game. Miguel scored 4 more points than Alonzo. How would I graph t

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2 years ago

If 1st and 4tg terms of G.p are 500 and 32 respectively it's second term is ?

bixtya [17]

Answer:

$T_{2} = 200$

Step-by-step explanation:

Given

Geometry Progression

$T_1 = 500$

$T_4 = 32$

Required

Calculate the second term

First, we need to write out the formula to calculate the nth term of a GP

$T_n = ar^{n-1}$

For first term: Tn = 500 and n = 1

$500 = ar^{1-1}$

$500 = ar^{0}$

$500 = a$

$a = 500$

For fought term: Tn = 32 and n = 4

$32 = ar^{4-1}$

$32 = ar^3$

Substitute 500 for a

$32 = 500 * r^3$

Make r^3 the subject

$r^3 = \frac{32}{500}$

$r^3 = 0.064$

Take cube roots

$\sqrt[3]{r^3} = \sqrt[3]{0.064}$

$r = \sqrt[3]{0.064}$

$r = 0.4$

Using: $T_n = ar^{n-1}$

$n = 2$ $r = 0.4$ and $a = 500$

$T_{2} = 500 * 0.4^{2-1}$

$T_{2} = 500 * 0.4^1$

$T_{2} = 500 * 0.4$

$T_{2} = 200$

<em>Hence, the second term is 200</em>

5 0

2 years ago