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agasfer [191]
3 years ago
7

A train is traveling at a constant speed and goes 7.5 kilometers in 6 minutes. At that rate:

Mathematics
2 answers:
Orlov [11]3 years ago
8 0

For distance in 1 minute, divide the distance for 6 minutes by 6 minutes:

7.5 km / 6 minutes = 1.25 km per minute.

For 100 minutes, multiply distance per minute by total minutes:

1.25 km per minute x 100 minutes = 125 km

nlexa [21]3 years ago
8 0

Answer:

1.25 km in 1 minute

125 km in 100 minutes

Step-by-step explanation:

Find its speed in km/min by dividing the km by number of minutes:

7.5/6

= 1.25

So, the train goes 1.25 km in 1 minute.

Using this speed, find how far it goes in 100 minutes, by multiplying the speed by 100:

1.25(100)

= 125

So, in 100 minutes, the train goes 125 km.

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3 years ago
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To find the area of a triangle, you multiply the base times the height and multiply it by 2.
In order to find the height, you need to do this in reverse.
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3 years ago
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Enter an equation for the function that includes the points.Give your answer in a(b)x. In the event that a=1 , give your answer
Andrews [41]

Answer:

f(x) = \frac{24}{25} * \frac{5}{6}^x

Step-by-step explanation:

Given

(x_1,y_1) = (2,\frac{2}{3})

(x_2,y_2) = (3,\frac{5}{9})

Required

Write the equation of the function f(x) = ab^x

Express the function as:

y = ab^x

In: (x_1,y_1) = (2,\frac{2}{3})

y = ab^x

\frac{2}{3} = a * b^2 --- (1)

In (x_2,y_2) = (3,\frac{5}{9})

y = ab^x

\frac{5}{9} = a * b^3 --- (2)

Divide (2) by (1)

\frac{5}{9}/\frac{2}{3} = \frac{a*b^3}{a*b^2}

\frac{5}{9}/\frac{2}{3} = b

\frac{5}{9}*\frac{3}{2} = b

\frac{5}{3}*\frac{1}{2} = b

\frac{5}{6} = b

b = \frac{5}{6}

Substitute 5/6 for b in (1)

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\frac{2}{3} = a * \frac{5}{6}^2

\frac{2}{3} = a * \frac{25}{36}

a = \frac{2}{3} * \frac{36}{25}

a = \frac{2}{1} * \frac{12}{25}

a = \frac{24}{25}

The function: f(x) = ab^x

f(x) = \frac{24}{25} * \frac{5}{6}^x

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Can someone help me with exercise 121?
yanalaym [24]
It would be
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