Can some help me with 13 14 15 and 16 please

Mathematics

1 answer:

lidiya [134]3 years ago

8 0

Sorry but the question don't pop up for me

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Write an equation that has a graph with the shape of y = x^2, but shifted left 3 units.

svetoff [14.1K]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\
% left side templates
\begin{array}{llll}
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
\end{array}\\\\
--------------------\\\\$

$\bf % template detailing
\bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\$

$\bf \bullet \textit{ vertical shift by }{{ D}}\\
\left. \qquad \right. if\ {{ D}}\textit{ is negative, downwards}\\\\
\left. \qquad \right. if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}$

now, with that template in mind, let's see

$\bf y=x^2\implies 
\begin{array}{llll}
y=(&1x&-0)^2\\
&B&C
\end{array}$

so, just change C to +3, thus C/B is 3/1

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Christian created a model

larisa86 [58]

Answer:

7 inches

Step-by-step explanation:

250.4/36= 6.955555 rounded to nearest inch is 7

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Answer:

5 ft

Step-by-step explanation:

Let the height of the previous jump be represented by j. Then 1.1j = 5.5 ft.

Dividing both sides by 1.1, we get j = 5 ft. This was the height of the previous jump.

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Which subtraction expression

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If you would like to know which subtraction expression has the difference 1 + 4i, you can calculate this using the following steps:

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b. (–2 + 6i) – (–1 – 2i) = <span>–2 + 6i + 1 + 2i = </span>–1 + 8i

c. (3 + 5i) – (2 – i) = 3 + 5i – 2 + i = 1 + 6i

d. (3 + 5i) – (2 + i) = 3 + 5i – 2 – i = 1 + 4i

The correct result would be <span>d. (3 + 5i) – (2 + i).</span>

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