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navik [9.2K]
3 years ago
7

Can some help me with 13 14 15 and 16 please

Mathematics
1 answer:
lidiya [134]3 years ago
8 0
Sorry but the question don't pop up for me
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Write a fraction that is equivalent to a terminating decimal between 0.5 and 0.75
fomenos
0.5 = 1/2 = 2/4 = 4/8 = 8/16 = 16/320.75 = 3/4 = 6/8 = 12/16 = 24/32
Then the fractions in between are 5/8, 9/16, 11/16, 17/32, 19/32, 21/32, 23/32
7 0
3 years ago
12=y-3y what's the answer
nevsk [136]
12=y-3y  Combine like terms
12=-2y  Divide
y=-6
8 0
3 years ago
Read 2 more answers
HELP ASAP!!! WILL GIVE BRAINLEIST!!!
netineya [11]

Answer:

The first question is (n*8) - 4

The second question is no.

Step-by-step explanation:

The first question, you add 8. The first is 1. 1 * 8 = 8 - 4 = 4.

Therefore, the equation is (n*8) - 4

The second question, you can plug in numbers. You can solve for a term.  -100 + 17 = -83. -83 is not a multiple of -4. -100 is not a term.

8 0
3 years ago
Use the data set to find the slope and y-intercept.
nika2105 [10]
Y-intercept =12
Slope : y2-Y1/x2-x1
8-10/2-1
Slope : -2
3 0
2 years ago
Suppose yoko borrows $3500 at an interest rate of 4% compounded each year Find the amount owed at the end of 1 year
olchik [2.2K]

Amount owed at the end of 1 year is 3640

<h3><u>Solution:</u></h3>

Given that yoko borrows $3500.

Rate of interest charged is 4% compounded each year

Need to determine amount owed at the end of 1 year.

In our case :

Borrowed Amount that is principal P = $3500

Rate of interest r = 4%

Duration = 1 year and as it is compounded yearly, number of times interest calculated in 1 year n = 1

<em><u>Formula for Amount of compounded yearly is as follows:</u></em>

A=p\left(1+\frac{r}{100}\right)^{n}

Where "p" is the principal

"r" is the rate of interest

"n" is the number of years

Substituting the values in above formula we get

\mathrm{A}=3500\left(1+\frac{4}{100}\right)^{1}

\begin{array}{l}{A=\frac{3500 \times 104}{100}} \\\\ {A=35 \times 104} \\\\ {A=3640}\end{array}

Hence amount owed at the end of 1 year is 3640

5 0
3 years ago
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