Answer:
He should have divided 12 ÷ 3 first.
Step-by-step explanation:
Following PEMDAS/BODMAS, the first step is solving equations in parentheses. Since the parentheses contain a multi-step equation, Jay needs to follow PEMDAS for inside the parentheses as well. Instead of adding 3+12 first, he should have done division first (12 ÷ 3).
How the problem should be solved:
-3 × (3 + 12 ÷ 3) - 4
-3 × (3 + 4) -4
-3 × 7 - 4
-21 - 4
-25
Answer:
33333333333
Step-by-step explanation:
488888888
3
7/9-1/3 or 7/9-3/9= 4/9 is the answer
Function is p(x)=(x-4)^5(x^2-16)(x^2-5x+4)(x^3-64)
first factor into (x-r1)(x-r2)... form
p(x)=(x-4)^5(x-4)(x+4)(x-4)(x-1)(x-4)(x^2+4x+16)
group the like ones
p(x)=(x-4)^8(x+4)^1(x-1)^1(x^2+4x+16)
multiplicity is how many times the root repeats in the function
for a root r₁, the root r₁ multiplicity 1 would be (x-r₁)^1, multility 2 would be (x-r₁)^2
so
p(x)=(x-4)^8(x+4)^1(x-1)^1(x^2+4x+16)
(x-4)^8 is the root 4, it has multiplicity 8
(x-(-4))^1 is the root -4 and has multiplicity 1
(x-1)^1 is the root 1 and has multiplity 1
(x^2+4x+16) is not on the real plane, but the roots are -2+2i√3 and -2-2i√3, each multiplicity 1 (but don't count them because they aren't real
baseically
(x-4)^8 is the root 4, it has multiplicity 8
(x-(-4))^1 is the root -4 and has multiplicity 1
(x-1)^1 is the root 1 and has multiplity 1
Step-by-step explanation:
- 5x²-45=0
- 5x²=45
- x²=9
- x=√9
- x=3
hope it helps.
