534 is correct tobthe math 9×6=54and 6×8=48 do it vertically
The number of customers I would have expected to win the prize is 6.
<h3>How many more customers would I have expected to win the prize?</h3>
Probability determines the chances that an event would happen. The probability the event occurs is 1 and the probability that the event does not occur is 0.
Based on the probability, the number of customers I would have expected to win: 0.18 x 300 = 36
How many more people I would have expected to win : 36 - 30 = 6
Please find attached the complete question. To learn more about probability, please check: brainly.com/question/13234031
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Here is a saying 5 and above give it a shove (round up) 4 and below go down low (round down). In your case you would leave it the same, because when rounding you would round to the nearest 10th.
Example:
54 would round down to 50 and 55 would be rounded up to 60.
Answer: The answer for this would be the rise over run. If you know what the rise over run expression is great. If not, here it is. The slope of a non-vertical line is the ratio of the amount it rises over some interval, over the length of that interval.
It is written like this rise/run.
Step-by-step explanation: Start from 8 and RISE (vertically) 4 places, the RUN (horizontally) and count until you get to -12. Then you take your numbers and divide.
Answer:
<em>Two possible answers below</em>
Step-by-step explanation:
<u>Probability and Sets</u>
We are given two sets: Students that play basketball and students that play baseball.
It's given there are 29 students in certain Algebra 2 class, 10 of which don't play any of the mentioned sports.
This leaves only 29-10=19 players of either baseball, basketball, or both sports. If one student is randomly selected, then the propability that they play basketball or baseball is:

P = 0.66
Note: if we are to calculate the probability to choose one student who plays only one of the sports, then we proceed as follows:
We also know 7 students play basketball and 14 play baseball. Since 14+7 =21, the difference of 21-19=2 students corresponds to those who play both sports.
Thus, there 19-2=17 students who play only one of the sports. The probability is:

P = 0.59