Last option, (-2,6) where the lines intercept / cross over each other.
Hope this helps!
Answer:
−48−[18−((−16)−(5−(4−7)))]
⇒ −48−[−18((−16)−(5−(−3)))]
⇒ −48[18−(−16)−8)]
⇒ −48[18−(−24)]
⇒ −48−(18+24)
⇒ −48−42
⇒ −90
Answer:
............................
Step-by-step explanation:
Answer:
BD = 3.75 units
Step-by-step explanation:
Given AD is an angle bisector then it divides the opposite side into segments tat are proportional to the other 2 sides, that is
=
, substitute values
=
( cross- multiply )
8 BD = 30 ( divide both sides by 8 )
BD = 3.75 units
Answer:
99% confidence interval is:
(0.00278 < P1 - P2< 0.15921)
Step-by-step explanation:
For calculating a confidence intervale for the difference between the proportions of workers in the two cities, we calculate the following:
![[(p_{1} - p_{2}) \pm z_{\alpha/2} \sqrt{\frac{p_{1}(1-p_{1})}{n_{1}} + \frac{p_{2}(1-p_{2})}{n_{2}} }](https://tex.z-dn.net/?f=%5B%28p_%7B1%7D%20-%20p_%7B2%7D%29%20%5Cpm%20z_%7B%5Calpha%2F2%7D%20%5Csqrt%7B%5Cfrac%7Bp_%7B1%7D%281-p_%7B1%7D%29%7D%7Bn_%7B1%7D%7D%20%2B%20%5Cfrac%7Bp_%7B2%7D%281-p_%7B2%7D%29%7D%7Bn_%7B2%7D%7D%20%7D)
Where
: proportion sample of individuals who worked
at more than one job in the city one
: Number of respondents in the city one
: proportion sample of individuals who worked
at more than one job in the city two
: Number of respondents in the city two
Then
α = 0.01 and α/2 = 0.005
and ![z_{\alpha/2} = 2.575](https://tex.z-dn.net/?f=z_%7B%5Calpha%2F2%7D%20%3D%202.575)
![p_{1} = \frac{112}{384} = 0.2916](https://tex.z-dn.net/?f=p_%7B1%7D%20%3D%20%5Cfrac%7B112%7D%7B384%7D%20%3D%200.2916)
![p_{2} = \frac{91}{432} = 0.2106](https://tex.z-dn.net/?f=p_%7B2%7D%20%3D%20%5Cfrac%7B91%7D%7B432%7D%20%3D%200.2106)
and ![n_{2}= 432](https://tex.z-dn.net/?f=n_%7B2%7D%3D%20432)
The confidence interval is:
![[(0.2916 - 0.2106) \pm 2.575 \sqrt{\frac{0.2916(1-0.2916)}{384} + \frac{0.2106(1-0.2106)}{432} }](https://tex.z-dn.net/?f=%5B%280.2916%20-%200.2106%29%20%5Cpm%202.575%20%5Csqrt%7B%5Cfrac%7B0.2916%281-0.2916%29%7D%7B384%7D%20%2B%20%5Cfrac%7B0.2106%281-0.2106%29%7D%7B432%7D%20%7D)
(0.00278 < P1 - P2< 0.15921)