Answer:
it would be 298.08
Step-by-step explanation:
Answer:
m∠K = 37° and n = 31
Step-by-step explanation:
A lot of math is about matching patterns. Here, the two patterns we want to match are different versions of the same Law of Cosines relation:
- a² = b² +c² -2bc·cos(A)
- k² = 31² +53² -2·31·53·cos(37°)
<h3>Comparison</h3>
Comparing the two equations, we note these correspondences:
Comparing these values to the given information, we see that ...
- KN = c = 53 . . . . . . . . . . matching values 53
- NM = a = k . . . . . . . . . . . matching values k
- KM = b = n = 31 . . . . . . . matching values 31
- ∠K = ∠A = 37° . . . . . . . matching side/angle names
Abby apparently knew that ∠K = 37° and n = 31.
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<em>Additional comment</em>
Side and angle naming for the Law of Sines and the Law of Cosines are as follows. The vertices of the triangle are labeled with single upper-case letters. The side opposite is labeled with the same lower-case letter, or with the two vertices at either end.
Vertex and angle K are opposite side k, also called side NM in this triangle.
<span> by taking integral we get
integral sec(x) (tan(x)+sec(x)) dx
applying integral we get
sec(x) (tan(x)+sec(x)) gives sec^2(x)+tan(x) sec(x)
= integral (sec^2(x)+tan(x) sec(x)) dx
Integrate the sum term by term
= integral sec^2(x) dx+ integral tan(x) sec(x) dx
For the integrand tan(x) sec(x), now we will use substitution
substitute u = sec(x) and du = tan(x) sec(x) dx
= integral 1 du+ integral sec^2(x) dx
The integral of sec^2(x) is tan(x)
= integral 1 du+tan(x)
The integral of 1 is u
= u+tan(x)+constant
Substitute the value of u which is equal to
= sec(x):
so our conclusion is
:tan(x)+sec(x)+constant
hope this helps</span>
The answer I believe it is, is b and the box would be -1
