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BigorU [14]
3 years ago
14

Complete to get an equal ratio 3x/y = ? /2y

Mathematics
1 answer:
amid [387]3 years ago
5 0

Answer:

6x

Step-by-step explanation:

3x/y=x/2y

Since 2y is 2X greater than y, 6x is 2X greater than 3x.

So,

The answer is 6x.

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1 inch = 2.54cm 1 mile = 1.6km a map has a scale of 1 inch represents 1 mile use the given conversions to show that 1cm on the m
lara31 [8.8K]
Note: 1 inch = 2.54 cm is an exact converion, while 1 mile=1.6km is only approximate.

Using conversion
1 inch=2.54 cm
1 mile = 1760*3*12 = 63360 in = 160934.4 cm 
If 1 inch = 1 mile, then 
2.54 cm : 1 mile = 1.609344 km
1 cm : 0.6336 km   (exactly), or
1 cm : 0.6 km (approximately)

Using both conversions:
1 inch = 2.54 cm : 1 mile = 1.6 km
=>
2.54 cm : 1.6 km
1 cm : 1.6/2.54=0.6299 km (approximately), or
1 cm : 0.6 km (approximately)
8 0
3 years ago
Examine the system of equations. −5x + 5y = 40 4x + 3y = 24 What is the solution?
Solnce55 [7]
-5x + 5y = 40             -20x +20y =160               -5x + 5(8) = 40
4x + 3y = 24               20x +15y =120                -5x + 40 = 40
                                           35y = 280                   -5x =0
                                               y = 8                         x = 0

Hope you understood this
3 0
3 years ago
Read 2 more answers
I NEED HELP ASAPPPP
Yuliya22 [10]
Pythagorean Theorem- A^2+B^2=C^2
1) 6^2+9^2= x^2
2) 36+81= 117
Square root 117 =10.82

Hope this helped :)
4 0
3 years ago
How do I solve this equation??(6g^5h-4)^3
Veseljchak [2.6K]
((6)^3 (g^5)^3 (h)^3 + (-4)^3)
(216 x g^15 x h^3 - 64
216g^15h^3 - 64
8 0
4 years ago
Fx) = x2 - 8x + 15<br> g(x) = x-3<br> h(x) = f(x)/g(x)
aev [14]

Answer: \Large\boxed{h(x)=x-5}

Step-by-step explanation:

\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\la\la\la\la\ddddddddddddddddddddddddddddddddcleverdddddd\ffffffffffffffffffffffffffffffffffffffff\pppppppppppppp\displaystyle\ \Large \boldsymbol{} h(x)=\frac{f(x)}{g(x)} =? \\\\\\f(x)=x^2-8x+15\\\\\\x^2-8x+\underbrace{15+1-1}_{15}=0 \\\\\\\underbrace{x^2-8x+16}_{(x-4)^2}-1=0 \\\\\\(x-4)^2-1\Longrightarrow f(x)=(x-5)(x-3)                                                     \displaystyle\ \Large \boldsymbol{} h(x)=\frac{(x-3)(x-5)}{(x-3)}=\boxed{x-5}                                          

8 0
3 years ago
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