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DerKrebs [107]
3 years ago
10

An investment pays 21% interest compounded weekly what percent as a decimal is the effective annual yield? Enter your answer as

a decimal rounded to four decimal places.
Mathematics
1 answer:
Troyanec [42]3 years ago
6 0

9514 1404 393

Answer:

  0.2332

Step-by-step explanation:

The relationship between the effective annual yield (e) and the nominal annual interest rate (r) compounded n times per year is ...

  e = (1 +r/n)^n -1

For weekly compounding, we have n=52, so ...

  e = (1 +0.21/52)^52 -1 = 0.2332 . . . . . . . about 23.32%

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3a^4(2b^6c^3)^2<br> Can someone help me simplify this?
Grace [21]
First you do 3a^4(2b^6c^3)^2
=12a^4b^12c^6
7 0
3 years ago
Use the quadratic expression 25x2−y2 to answer the questions.
vova2212 [387]

Answer:

Part A)

This quadratic expression can be factored by using the difference of squares pattern.

Part B) (5x+y) and (5x-y)

Step-by-step explanation:

Given:

25x^2-y^2

above polynomial can be factorize by using difference of squares formula

a2-b2=(a+b)(a-b)

25x^2-y^2= (5x-y)(5x+y)

so for part A)

correct option is  This quadratic expression can be factored by using the difference of squares pattern.

Part B)

As factored above in part A,

the factors of given polynomial 25x^2-y^2 are (5x+y)(5x-y)

so for part B) correct options are (5x+y) and (5x-y) !

8 0
4 years ago
How do you use the fundamental counting principle?
qaws [65]
In the fundamental counting principle, you are multiplying to get the total number of possibilities as a result. For example, if you have 5 different types of bread, 8 types of cheese, and 6 types of meat, you have 240 choices (8 x 6 x 5).
7 0
3 years ago
What is the value of k in the equation StartFraction k Over 3 EndFraction minus 5 = 34?
Oksanka [162]

Answer:

k=117

Step-by-step explanation:

To solve, we need to isolate the variable, k

k/3 -5 = 34

Add 5 to both sides to "reverse" the subtraction

k/3=39

Multiply both sides by 3 to "reverse" the division

3*k/3=39*3

k=117

Hope this helps! :)

4 0
4 years ago
Read 2 more answers
Ecuación de la hipérbola con centro en (0;0), focos en abrir paréntesis 0 coma espacio menos raíz cuadrada de 28 cerrar paréntes
yaroslaw [1]

Answer:

\frac{y^{2}}{25}-\frac{x^{2}}{3}=1

Step-by-step explanation:

Para resolver este problema debemos tomar en cuenta los datos que nos dan y la ecuación de una hipérbola. Comencemos con los datos:

centro: (0,0)

focos: (0,-\sqrt{28}),(0,\sqrt{28})

eje conjugado = 2\sqrt{3}

por los focos podemos ver que la hipérbola se dirige hacia el eje y, por lo que debemos tomar la siguiente forma de la ecuación de la parábola:

\frac{y^{2}}{a^{2}}+\frac{x^{2}}{b^{2}}=1

de los focos podemos obtener que:

c=\sqrt{28}

y del eje conjugado podemos saber que al dividir la longitud del eje conjugado dentro de 2 obtenemos b, así que:

b=\sqrt{3}

podemos utilizar la siguiente fórmula para obtener a:

c^{2}-a^{2}=b^{2}

si despejamos a en la ecuación obtenemos lo siguiente:

a=\sqrt{c^{2}-b^{2}}

ahora podemos sustituir los valores:

a=\sqrt{(\sqrt{28})^{2}-(\sqrt{3})^{2}}

a=\sqrt{28-3}

a=\sqrt{25}

a=5

así que media vez conozcamos a, podemos sustituir los datos en la ecuación de la hipérbola así que obtenemos lo siguiente:

\frac{y^{2}}{a^{2}}+\frac{x^{2}}{b^{2}}=1

\frac{y^{2}}{(5)^{2}}+\frac{x^{2}}{(\sqrt{3})^{2}}=1

\frac{y^{2}}{25}+\frac{x^{2}}{3}=1

si graficamos la hipérbola, queda como en el documento adjunto.

7 0
3 years ago
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