First we write the mathematical model in a generic way:
"The stopping distance of an automobile is directly proportional to the square of its speed v"
d = kv ^ 2
Where,
k: proportionality constant.
We now look for the value of K:
d = kv ^ 2
90 = k ((70) * (5280/3600)) ^ 2
k = 90 / ((70) * (5280/3600)) ^ 2
k = 0.008538539 s ^ 2 / feet
The equation will then be:
d = (0.008538539) * v ^ 2
For v = 71 miles per hour we have:
d = (0.008538539) * ((71) * (5280/3600)) ^ 2
d = 92.6 feet
Answer:
a mathematical model that gives the stopping distance in terms of its speed v is:
d = (0.008538539) * v ^ 2
The stopping distance if the brakes are applied when the car is traveling at 71 miles per hour is:
d = 92.6 feet
F(x)=x2,
g(x)=f(3x)=(3x)2=9x2
Now to graph y=9x2. This is a parabola (U-shape), vertex at (0, 0), symmetric aroung y axis. When x=1/3 or -1/3, then y=1.
So, try to draw the graph.
Answer:
C) 7c+6s-63
Step-by-step explanation:
set up this equation because you are adding the two expressions
combine like terms
The answer is definitely a
O get the Least Common Multiple (LCM) of 15 and 8 we need to factor each value first and then we choose all the factors which appear in any column and multiply them:
<span><span>15: 35</span><span>8: 222 </span><span>LCM: 22235</span></span>
<span>The Least Common Multiple (LCM) is: 2 x 2 x 2 x 3 x 5 = 120</span>
