Step-by-step explanation:
Give the first 8 terms of the sequence. a1= -1, a2=2, a[n]=a[n-2](3-a[n-1])
Given
first term a1 = -2
second term a2 = 2
We are to get the first 8 terms. Given the sequence
a[n]=a[n-2](3-a[n-1])
a[3]=a[3-2](3-a[3-1])
a[3]=a[1](3-a[2])
a[3]=-2(3-2)
a3 = -2
a[n]=a[n-2](3-a[n-1])
a[4]=a[4-2](3-a[4-1])
a[4]=a[2](3-a[3])
a[4]=2(3+2)
a4= 10
a[5]=a[n-2](3-a[n-1])
a[5]=a[5-2](3-a[5-1])
a[5]=a[3](3-a[4])
a[5]=-3(3-10)
a5 = -3(-7)
a5 = 21
a[6]=a[n-2](3-a[n-1])
a[6]=a[6-2](3-a[6-1])
a[6]=a[4](3-a[5])
a[6]= 10(3-21)
a6 = 10(-18)
a6 = -180
a[n]=a[n-2](3-a[n-1])
a[7]=a[7-2](3-a[7-1])
a[7]=a[5](3-a[6])
a[7]= 21(3+180)
a7 = 21(183)
a7 = 3,843
a[8]=a[n-2](3-a[n-1])
a[8]=a[8-2](3-a[8-1])
a[8]=a[6](3-a[7])
a[8]=-180(3-3843)
a8 = -180(-3840)
a8 = 691,200
P - 2
Enjoy!! :) (answer needs to be at least 20 characters long sooo)
Answer:
A=8
Step-by-step explanation:
If you use the formula 30-60-90 which is a-radical 3a-2a
since the hypotenuse is 2a it equals 16
therefore if its 2a all you need to do is divide it where then you get 8.
13.3cm rounded to the nearest 10th
