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ch4aika [34]
3 years ago
6

How would the bonding of a purine with a purine alter the DNA molecule?

Biology
1 answer:
Dovator [93]3 years ago
6 0

Answer:

Penicillin is hydrolyzed and thereby rendered inactive by penicillinase (also known as β-lactamase), an enzyme present in some resistant bacteria. the mass of this enzyme in staphylococcus aureus is 29.6 kd. the amount of penicillin hydrolyzed in 1 minute in a 10-ml solution containing 10-9 g of purified penicillinase was measured as a function of the concentration of penicillin. assume that the concentration of penicillin does not change appreciably during the assay. penicillin(μm) amount hydrolyzed(nmol) 1 0.11 3 0.25 5 0.34 10 0.45 30 0.58 50 0.61 (a) plot v0 versus [s] and 1/v0 versus 1/[s] for these data. does penicillinase appear to obey michaelis-menten kinetics? if so, what is the value of km? (b) what is the value of vmax? (c) what is the turnover number of penicillinase under these experimental conditions? assume one active site per enzyme molecule.

Explanation:

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PLZ HELP meh!!!!!!!!!!!!!!!!!!!!
melomori [17]

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to be able to study how other organisms are affected by the species


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3 years ago
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Following a lengthy marathon, a runner feels out of breath and is experiencing muscle soreness. Explain
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What pattern of migration do whales follow?
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3 years ago
The overall result of the proton-proton chain is that ________
Delicious77 [7]
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Hope this helps!

7 0
4 years ago
In a dihybrid cross involving two autosomal traits on different chromosomes in which the parents are purebred for the opposite f
Simora [160]

Answer:

The question lacks options, the options are:

A) 1 out of 16

B) 3 out of 16

C) 6 out of 16

D) 9 out of 16

The answer is 1 out of 16

Explanation:

This is a DIHYBRID cross because it involves two different genes coding for distinct traits. One of the traits will be dominant while the other recessive. Hence, parents that are purebred for opposite forms of the trait means that one parent is homozygous dominant while the other is homozygous recessive. When these two parents cross, they produce F1 offsprings that all possess the dominant trait but heterozygous/hybrids.

When these hybrids are self-crossed, they produce four different combinations of gametes which when crossed using a punnet square will result in F2 offsprings with a 9:3:3:1 phenotypic ratio according to Mendel's observation.

9 represents offsprings that are dominant for both traits

The two 3's represents offsprings that are recessive for one trait and dominant for the other respectively.

1 represents offsprings that are homozygous recessive for both traits.

Hence, 1 out of 16 offsprings will be homozygous recessive for both traits.

4 0
3 years ago
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