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shtirl [24]
3 years ago
9

Please help with this asap I'll mark brainlyest​

Mathematics
1 answer:
tekilochka [14]3 years ago
4 0

False

I hope I've helped!

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A used car has a value of 15,250 when it’s purchased in 2012. The value of the car decreases at a rate of 7.5% per year
kotegsom [21]

p=15250

r=7.5/100=0.075

y = 15250*(1 - 0.075)^x

after 8 years it would be

x = 8

y = 15250*(1 - 0.075)^8

y = $8,173.42

after 8 years the value of the car is going to be $8,173.42

8 0
3 years ago
1 - (2n + 9) = 4(1-2)
Vikki [24]

Answer:

n=-2

Step-by-step explanation:

1−(2n+9)=4(1−2)

1+−1(2n+9)=4(1−2)

1+−1(2n)+(−1)(9)=4(1−2)

1+−2n+−9=4(1−2)

1+−2n+−9=−4

(−2n)+(1+−9)=−4

−2n+−8=−4

−2n−8=−4

−2n−8+8=−4+8

−2n=4

Divide both sides by -2

-2n/2=4/-2

n=-2

6 0
3 years ago
Read 2 more answers
The cost of 3 notebooks and 2 pencils is $5.10. At the same prices, the cost of 2 notebooks and 3 pencils is $4.65. What is the
Pepsi [2]

Answer:

$1.95

Step-by-step explanation:

notebook = n

pencil = p

3n + 2p = 5.10

2n + 3p = 4.65

multiply top equation by 2 and bottom by 3

6n + 4p = 10.20

6n +9p = 13.95

subtract bottom equation from the top equation

-5p = -3.75

divide by 5, negatives cancel out

p  = 0.75

sub p into either equation, I chose the original top equation

3n + 2(0.75) = 5.10

3n + 1.50 = 5.10

subtract 1.50 from both sides

3n = 3.60

divide both sides by 3

n = 1.20

p = 0.75

n + p = 1.95 (the fourth option)

4 0
3 years ago
Find a_1 and d for an arithmetic sequence with these terms. a_4=9and a_7=18
jonny [76]
\bf \begin{array}{llll}
term&value\\
-----&-----\\
a_4&9\\
a_5&9+d\\
a_6&(9+d)+d\\
&9+2d\\
a_7&(9+2d)+d\\
&9+3d=\underline{18}
\end{array}\\\\
-------------------------------\\\\
9+3d=18\implies 3d=9\implies d=\cfrac{9}{3}\implies \boxed{d=3}

\bf n^{th}\textit{ term of an arithmetic sequence}\\\\
a_n=a_1+(n-1)d\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
d=\textit{common difference}\\
----------\\
n=7\\
d=3
\end{cases}
\\\\\\
a_7=a_1+(7-1)d\implies 18=a_1+(7-1)3\implies 18=a_1+18
\\\\\\
18-18=a_1\implies \boxed{0=a_1}
3 0
4 years ago
50 people took a rest before the test they predicted whether they would pass or fail 30 People predicted they would pass 26 of t
Gre4nikov [31]
37-26=11
26+4+11=41
50-41=9
5 0
3 years ago
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