To find the x-intercept<span> of a given linear equation, plug in 0 for '</span>y' and solve for 'x<span>'. To find the </span>y-intercept, plug 0 in for 'x' and solve for '<span>y"</span>
Answer: 10.8
Step-by-step explanation: the pythagorean theorem is A sqaured or A^2 + B^2 or B squared equals C^2 or C squared so 10 squared as is the first number is 100 and 4 squared as is the second number is 16 add the two to get 116 but since your answer is squared you need to take the square root which means your answer is 10.7703296143 but since your rounding to the tenths place your answer is 10.8
Answer:
1
Step-by-step explanation:
one quarter = 25%.
The one spot looks about one quarter.
14/21 is 2/3 simplified.
9/15 is 3/5 simplified.
and 3/8 can not be simplified, so it's 3/8
Ok, I'm going to start off saying there is probably an easier way of doing this that's right in front of my face, but I can't see it so I'm going to use Heron's formula, which is A=√[s(s-a)(s-b)(s-c)] where A is the area, s is the semiperimeter (half of the perimeter), and a, b, and c are the side lengths.
Substitute the known values into the formula:
x√10=√{[(x+x+1+2x-1)/2][({x+x+1+2x-1}/2)-x][({x+x+1+2x-1}/2)-(x+1)][({x+x+1+2x-1}/2)-(2x-1)]}
Simplify:
<span>x√10=√{[4x/2][(4x/2)-x][(4x/2)-(x+1)][(4x/2)-(2x-1)]}</span>
<span>x√10=√[2x(2x-x)(2x-x-1)(2x-2x+1)]</span>
<span>x√10=√[2x(x)(x-1)(1)]</span>
<span>x√10=√[2x²(x-1)]</span>
<span>x√10=√(2x³-2x²)</span>
<span>10x²=2x³-2x²</span>
<span>2x³-12x²=0</span>
<span>2x²(x-6)=0</span>
<span>2x²=0 or x-6=0</span>
<span>x=0 or x=6</span>
<span>Therefore, x=6 (you can't have a length of 0).</span>
