Given:
A quadrilateral WXYZ has vertices W(3, −5), X(1, −3), Y(−1, −5), and Z(1,−7).
Rule of rotation is 
.
To find:
The vertices after rotation.
Solution:
We know that, means 90 degrees counterclockwise rotation around the origin.
So, the rule of rotation is defined as
Using this rule, we get
Therefore, the required vertices after rotation are W'(5,3), X'(3,1),Y'(5,-1) and Z'(7,1).
how many solutions do intersecting lines have? - 0,1 or infinitely many
how many solutions do parallel lines have? - 0 or infinitely many
if you are looking at a graph and trying to find a solution what are you looking for? - for the point(s) when the graphs intersect
Answer:
just remember this:
negative x negative = positive
positive x positive = positive
postive x negative = negative
negative x postive= negative
lookon bbcbitesize for adding negatives and positive rule
Answer:
Throughout the clarification segment elsewhere here, the definition including its query is mentioned.
Step-by-step explanation:
- The error margin applies to the difference between the results of this survey as well as the real estimates.
- This may occur for several factors, such as limited sample size, incomplete survey, people's biased answers, etc.
- It shows us where the outcomes of this study are not reliable and 100% right and, for several different reasons, there seems to be a disparity between some of the published and real statistics.
In addition to making audiences and people believe that perhaps the recorded results could not be considered as 100 percent reliable so there's still a variety of errors throughout themselves, it is important to incorporate this detail in polling data.
Answer:
x = -1 ± 2i
Step-by-step explanation:
The standard form of a quadratic equation is ax² + bx + c = 0, and the quadratic formula is x= [−b ± √(b
² - 4ac) ] / 2a
In this case, a = 1, b = 2 and c = 5. Now you have to substitute in the quadratic formula:
x= [−b ± √(b
² - 4ac) ] / 2a
x= [−2 ± √(2
² - 4*1*5) ] / 2*1
x= [−2 ± √(4 - 20) ] / 2
x= [−2 ± √(-16) ] / 2
Since the square root is negative, you have to use imaginary numbers to continue solving the equation. Remmber that √(-1) = i.
x= [−2 ± √(-16) ] / 2
x= [−2 ± √(16)i ] / 2
x= [−2 ± 4i ] / 2
x1 = [−2 + 4i ] / 2
x1 = -1 + 2i
x2 = [−2 - 4i ] / 2
x2 = -1 - 2i
So the answers of x are -1 ± 2i
