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stepan [7]
2 years ago
14

There is a pair of x and y values that make each equation true in this system of equations

Mathematics
1 answer:
MAXImum [283]2 years ago
5 0

Given Equations

  • 5x+3y=8--(1)
  • 4x+7y=34--(2)

Let it has solution (x,y)

Add both

\\ \sf\longmapsto 5x+4x+3y+7y=8+34

\\ \sf\longmapsto 9x+10y=42

It will also have same solution (x,y)

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3 years ago
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Ede4ka [16]

Answer:

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Step-by-step explanation:

4 0
3 years ago
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A quadratic equation ax^2+bx+c=0 has -11 and 4 as solutions. Find the values of b and c if the value of a is 1 (hint, use zero f
Alina [70]

Answer:

b = 7, c = -44

Step-by-step explanation:

If the quadratic equation has the solutions -11 and 4, the two factors are:

(x+11)(x-4)=0

Since when we use the zero factor property we get

x+11=0 ⇒ x= -11

x-4=0 ⇒  x=4

Thus, we have used the zero factor property in reverse to find the factorization of the quadratic equation.

Now we develop the multiplications between parenthesis:

(x+11)(x-4)=0\\x^2-4x+11x-44=0\\x^2+7x-44=0

So b is the number that accompanies the x: b = 7

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3 0
3 years ago
Which expression is equivalent to x² + 2x + 2?
melisa1 [442]

Answer:

(x+1-i)(x+1+i)

Step-by-step explanation:

(x+1-i)(x+1+i)\\\\=(x+1)^2 -i^2~~~~~~~~~~~~~;[a^2 -b^2 = (a+b)(a-b)]\\\\=x^2 +2x +1 -(-1)\\\\=x^2 +2x +1+1\\\\=x^2 +2x +2

4 0
1 year ago
Given the trinomial x^2+bx+c where both the first and second signs are positive, the signs of the factors will be: A. both negat
Lunna [17]
The answer here is C. The sign of the factors are both positive. We can use the FOIL method as reference in determining the sign of the factors. The 3rd term C is positive; therefore our only option is either both negative or both positive. Looking the middle term, which is positive, we know that the middle term is the sum of the outer and inner in FOIL method, which means, signs of the factors must be both positive
7 0
3 years ago
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