What is the Y intercept of the line described for the equation below?y=4x-9

Mathematics

2 answers:

Vladimir [108]3 years ago

8 0

Answer: Assuming that it's already in the standard form - y=mx+b | Your Y-Intercept is going to be -9

Step-by-step explanation:

Using the equation y=mx+b, anything that is in place of the (b) is your Y-Intercept and your slope is (m)

julia-pushkina [17]3 years ago

8 0

Answer: The y intercept is (0, -9)

Step-by-step explanation:

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When I double my number, subtract three, subtract my number, and add four, I get my number plus two. What is my number?

marishachu [46]

Answer:

Any real number

Step-by-step explanation:

Let your no.= x

double the number=2x

add 4 = 2x+4

subtract same number=2x+4-x

subtract 3=2x+4-x-3

get number plus 1=x+1

so equation we get

2x+4-x-3=x+1

x+1=x+1

x=x

it means x is equal to all real number

So your number can be any real number

7 0

2 years ago

If g(x)=4x^2-16 we’re shifted 9 united to the right and 1 down, what would the new equation be?

Inessa05 [86]

Shown in the graph

<h2>Explanation:</h2>

Using graph tools we can graph the function:

$g(x)=4x^2-16$

which is the red graph shown below. As you can see, this is a parabola. The rule for vertical and horizontal shifts is as follows:

$Let \ c \ be \ a \ positive \ real \ number. \ \mathbf{Vertical \ and \ horizontal \ shifts} \\ in \ the \ graph \ of \ y=f(x) \ are \ represented \ as \ follows:$

$\bullet \ Vertical \ shift \ c \ units \ \mathbf{upward}: \\ h(x)=f(x)+c \\ \\ \bullet \ Vertical \ shift \ c \ units \ \mathbf{downward}: \\ h(x)=f(x)-c \\ \\ \bullet \ Horizontal \ shift \ c \ units \ to \ the \ right \ \mathbf{right}: \\ h(x)=f(x-c) \\ \\ \bullet \ Horizontal \ shift \ c \ units \ to \ the \ left \ \mathbf{left}: \\ h(x)=f(x+c)$