The question is asking to write and equation by using the two variable in the standard form that ca be used to describe the velocity of thecar at different times and base on my calculation, I would say that the answer would be v=4t+39. I hope you are satisfied with my answer and feel free to ask for more
Answer:
D. B,C,A
Step-by-step explanation:
A= |7|=7
B= -6
C= |-5|=5
so this means that B<C<A = -6<5<7
so; B,C,A = -6,7,5
The formula for distance is equal to:
d = v * t
where d is distance, v is velocity or speed, and t is
time
Since the distance travelled by the two airplane is
similar, therefore we can create the initial equation:
v1 * t1 = v2 * t2
We know that v1 = 496, and v2 = 558 so:
496 t1 = 558 t2
or
x = 558 t2 / 496
We also know that airplane 1 travelled 30 minutes (0.5
hours) earlier than airplane 2, therefore:
x = t2 + 0.5
Hence,
496 (t2 + 0.5) = 558 t2
496 t2 + 248 = 558 t2
t2 = 4 hours
x = t2 + 0.5 = 4 + 0.5
x = 4.5 hours
So the equation is:
x = 558 t2 / 496
And the first plane travelled:
x = 4.5 hours
0.4 and 0.40 are equal. That zero on the hundredths place does not matter.
Answer:
Step-by-step explanation:
False. If L does not equal W the diagonals are not perpendicular. If L=W then they are perpendicular but that is a square and a special case which is not always true of a rectangle.
