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maxonik [38]
3 years ago
13

Find the midpoint of the segment with the given endpoints. (-7, -9) and (-2,7)

Mathematics
1 answer:
jolli1 [7]3 years ago
5 0

Answer:

(-9/2,-1)

Step-by-step explanation:

Use the midpoint formula to find the midpoint of the line segment.

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Ruth has $15000 to invest. She invests some of her money earned 7% simple interest and the rest earned 5.5%. If the total intere
svetlana [45]
Invested at 7%:  s
Invested at 5.5%:  f
Then s+f=$15000, or f= $15000-s

Then add together the 2 interest amounts:

i = s(0.07) at 7%
i = f(0.055) at 5.5%

Then 0.07s + (15000-s)(0.055) = $952.50

Solve this for s, the amt. invested at 7%:

0.07s + 15000(0.055) - 0.055s = 952.50
Combining the s terms, 

0.015s = 952.50-825
               
                 952.50-825 
Then s = ------------------- = 8500
                        0.015

Ruth invests $8500 at 7% and $6500 at 5.5%.
5 0
3 years ago
In 2008, the minimum wage was $8 per hour. Now it is $13. By what percent did the price change?
MrRa [10]

Answer:

62.5%

Step-by-step explanation:

13-8=5

5/8 × 100=62.5

6 0
3 years ago
12 − x = 7x + 32
Arada [10]

Answer:

C. the subtraction property of equality

Step-by-step explanation:

12-x = 7x + 32

Step - 1: -x = 7x + 20

In that case, we just swap 12 from the left side to right side, and then we subtract 12 from 32 which is on the right side. Therefore, we do not multiply, divide or add anything. So, the option "C" is correct.

Step 2: -8x = 20

In that case, we again subtract 12 by interchanging the side. Moreover, we change the side of 7x to deduct it from -x.

Therefore, in both the cases, we use the subtract property of equality.

5 0
3 years ago
9x-3=5x+9 solve for x
vovikov84 [41]

Answer:

x = -3

Step-by-step explanation:

3 0
4 years ago
Read 2 more answers
What is the simplified form of the quantity of x plus 4, all over the quantity of 7 − the quantity of x plus 3, all over the qua
scoundrel [369]
\frac{x + 4}{7} -\frac{x + 3}{x + 5} =\frac{(x + 4)(x + 5)}{7(x + 5)} -\frac{7(x + 3)}{7(x + 5)} =\frac{x(x + 5) + 4(x + 5)}{7(x) + 7(5)} - \frac{7(x) + 7(3)}{7(x) + 7(5)} =\frac{x(x) + x(5) + 4(x) + 4(5)}{7x + 35} - \frac{7x + 21}{7x + 35} =\frac{x^{2} + 5x + 4x + 20}{7x + 35} -\frac{7x + 21}{7x + 35} =\frac{x^{2} + 9x + 20}{7x + 35} - \frac{7x + 21}{7x + 35} =\frac{(x^{2} + 9x + 20) - (7x + 21)}{7x + 35} =\frac{x^{2} + (9x - 7x) + (20 - 21)}{7x + 35} =\frac{x^{2} + 2x -1}{7x + 35}
3 0
3 years ago
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