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tester [92]
3 years ago
8

Find the value of 4y - 8 given that -3y + 3 = 6

Mathematics
1 answer:
tatiyna3 years ago
4 0

Answer:-12

Step-by-step explanation:6-3=3/(-3)=-1

4(-1)-8=-12

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Write a numerical expression to match the written expression below: Twenty-three less than the sum of forty-nine and thirty-seve
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Answer:

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3 years ago
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Find the lateral area and surface area of a cone with a radius of 12 and a height of 21
marishachu [46]

Answer:

The Lateral Surface Area is 911.32 square unit and

Total Surface Area is 1361.7 square unit.

Step-by-step explanation:

For a given Cone

Radius (r) = 12

Height (h) = 21

<u>For Lateral Surface Area</u>

<h3><u>Formula</u><u>:</u> </h3>

A = πr√r² + h²

A = 3.14 × 12 × √(12)² + (21)²

A = 3.14 × 12 × √144 + 441

A = 3.14 × 12 × √585

A = 37.68 × 24.18

A = 911.32 square unit

Now,

<u>For</u><u> </u><u>Total</u><u> Surface Area</u>

<h3><u>Formula:</u></h3>

A = πrl + πr²

For Slant height (l)

l² = r² + h²

l² = (12)² + (21)²

l² = 144 + 441

l² = 585

l = 24.18

So,

A = πrl + πr²

A = πr(l + r)

A = 3.14 × 12 × (24.14 + 12)

A = 3.14 × 12 × 36.14

A = 1361.7 square unit

Thus, The <u>Lateral Surface Area</u> is 911.32 square unit and <u>T</u><u>otal Surface Area</u> is 1361.7 square unit.

<u>-TheUnknownScientist</u>

6 0
3 years ago
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While visiting a​ memorial, a person approximated the angle of elevation to the top of the memorial to be 35º. After walking 255
Alenkasestr [34]

Draw a diagram to illustrate the problem as shown in the figure below.

Let h the height of the hill. =

At position A, the angle of elevation is 40°, and the horizontal distance to the foot of the hill is x.

By definition,

tan(40°) = h/x h = x tan40 = 0.8391x

(1)

At position B, Joe is (x - 450) ft from the foot of the hill. His angle of elevation is

40 + 18 = 58°.

By definition, tan(58°) = h/(x - 450)

h = (x - 450) tan(58°) = 1.6003(x-450)

h = 1.6003x - 720.135 (2)

Equate (1) and (2).

1.6003x - 720.135 = 0.8391x 0.7612x = 720.135

x = 946.0523

From (1), obtain

h = 0.8391*946.0523 = 793.8 ft

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3 years ago
Neptune is an average distance of 4.5 × 10^9 km from the Sun. Estimate the length of the Neptunian year using the fact that the
zlopas [31]

Answer:

Answer:

164.32 earth year

Step-by-step explanation:

distance of Neptune, Rn = 4.5 x 10^9 km

distance of earth, Re = 1.5 x 10^8 km

time period of earth, Te = 1 year

let the time period of Neptune is Tn.

According to the Kepler's third law

T² ∝ R³

\left ( \frac{T_{n}}{T_{e}} \right )^{2}=\left ( \frac{R_{n}}{R_{e}} \right )^{3}

\left ( \frac{T_{n}}{1} \right )^{2}=\left ( \frac{4.5\times10^{9}}}{1.5\times10^{8}}} \right )^{3}

Tn = 164.32 earth years

Thus, the neptune year is equal to 164.32 earth year.

Step-by-step explanation:

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3 years ago
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The answer is (-3+2)^2 =1
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