<span>During
an investigation, a student determines that a copper sample has a
density of 8.10 g/ml. What is the students percent error of the accepted
density for copper is 8.96 g/ml
</span>
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1 answer:
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To solve this problem it is necessary to apply the second derivative of the function to find the maximum time reference and thus calculate the maximum voltage.
With the maximum voltage by Ohm's Law it is possible to find the maximum current.
Ohm's law defines that
E = I*R
Where,
I = Current
R= Resistance
On the other hand by faraday studies and the potential can be expressed at the rate of change of the electric flow, that is
Replacing with our values we have that
The second derivative is
When E' = 0 we have a Maximum, then
0 = -36t+36
t = 1
Therefore when the time is 1s E has a Maximum, replacing at the function
Then the maximum current will be given by
Therefore the maximum current induced in the ring is 6.42A
Explanation:
It is given that,
When the front wheels are over the scale, the weight recorded by the scale is 5800 N, F₁ = 5800 N
When the rear wheels are over the scale, the scale reads 6500 N, F₂ = 6500
The distance between the front and rear wheels is measured to be 3.20 m, x₂ = 3.2 m
We need to find the location of center of mass behind the front wheels. Let the center of is located at a distance of x₁. Thus balancing the torques we get :
On solving the above equation we get, x₂ = 1.69 m
So, the center of mass is located at a distance of 1.69 meters behind the front wheels.