Answer:
The power dissipated is reduced by a factor of 2
Explanation:
The power dissipated by a resistor is given by:
where
I is the current
R is the resistance
by using Ohm's law, , we can rewrite the previous equation in terms of the voltage applied across the resistor (V):
In this problem, the resistance of the element is doubled, while the voltage is kept constant. So we have while V remains the same; substituting into the formula, we have:
so, the power dissipated is reduced by a factor 2.
Answer:
98.11 I think
Explanation:
I really hope this helps have a wonderful day
Answer:
The current is
Explanation:
From the question we are told that
The length of the solenoid is
The radius is
The number of turn is
The magnetic field is
The magnetic field produced is mathematically represented as
making the subject
Where is the permeability of free space with values
substituting values
The Force exerted on the student is 100 N
<u>Explanation:</u>
Given data
mass= 40 kg
acceleration= 2.5 m/s2
To find the force, we have the formula
Force= mass × acceleration
Force= 40 ×2.5
Force=100 N
The Force exerted on the student is 100 N
Answer:
C = 2.9 10⁻⁵ F = 29 μF
Explanation:
In this exercise we must use that the voltage is
V = i X
i = V/X
where X is the impedance of the system
in this case they ask us to treat the system as an RLC circuit in this case therefore the impedance is
X =
tells us to take inductance L = 0.
The angular velocity is
w = 2π f
the current is required to be half the current at high frequency.
Let's analyze the situation at high frequency (high angular velocity) the capacitive impedance is very small
→0 when w → ∞
therefore in this frequency regime
X₀ =
the very small fraction for which we can despise it
X₀ = R
to halve the current at f = 200 H, from equation 1 we obtain
X = 2X₀
let's write the two equations of inductance
X₀ = R w → ∞
X= 2X₀ = w = 2π 200
we solve the system
2R = \sqrt{R^2 +( \frac{1}{wC} )^2 }
4 R² = R² + 1 / (wC) ²
1 / (wC) ² = 3 R²
w C =
C =
let's calculate
C =
C = 2.9 10⁻⁵ F
C = 29 μF