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4 years ago

At what rate is 444kg object accelerating if a force of 7,700N is applied to it?

Physics

1 answer:

vlabodo [156]4 years ago

7 0

Answer:

646,800

Explanation:

If you multiply the 7,700N and the 444kg your answer would be 646,800.

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The net force acting on an object in the horizontal direction is 25 newtons, and the force acting in the vertical direction is 1

Zina [86]

The angle is found by taking the arctangent of the vertical angle divided by the horizontal angle
θ = arctan(18/25) = 35.75°
36° is the closest answer.

4 0

4 years ago

A proton moves along the x-axis with vx=1.0×107m/s. As it passes the origin, what are the strength and direction of the magnetic

Sunny_sXe [5.5K]

Answer:

Magnetic field will be ZERO at the given position

Explanation:

As we know that the magnetic field due to moving charge is given as

$B = \frac{\mu_0 qv sin\theta}{4\pi r^2}$

so here we know that for the direction of magnetic field we will use

$\hat B = \hat v \times \hat r$

so we have

$\hat B = \hat i \times (\hat i + 0\hat j + 0\hat k)$

so magnetic field must be ZERO

So whenever charge is moving along the same direction where the position vector is given then magnetic field will be zero

3 0

3 years ago

cycling at 13.0 m/s on your new aero carbon fiber bike, how much times would it take a pro cyclist to ride in 120 km? Give your

sp2606 [1]

We have that the time in seconds, minutes, and hours is

$t=1.083*10^{-4}s$

$T_{min}=1.805*10^{-6}min$

$T_{hours}=3.0083*10^{-8}hours$

From the Question we are told that

Velocity $v=13.0m/s$

Distance $d=120 km$

Generally the equation for the Time is mathematically given as

$t=\frac{13}{120*10^3}\\\\t=1.083*10^{-4}s$

Therefore

$T_{min}=1.083*10^{-4}s/60$

$T_{min}=1.805*10^{-6}min$

And

$T_{hours}=T_{min}/60$

$T_{hours}=3.0083*10^{-8}hours$

For more information on this visit

brainly.com/question/12319416?referrer=searchResults

4 0

3 years ago

Early one October, you go to a pumpkin patch to select your Halloween pumpkin. You lift the 2.9 kg pumpkin to a height of 1.5 m

Katen [24]

Answer:

Work done in lifting to a height of 1.5 m is 42.63 J.

Work done in carrying it to 50 m is 0 J

Explanation:

Given:

Mass of the pumpkin (m) = 2.9 kg

Vertical displacement of the pumpkin (y) = 1.5 m

Horizontal displacement of the pumpkin (x) = 50 m

Acceleration due to gravity (g) = 9.8 m/s²

Work done by a force is given by the formula:

$W=FS\cos\theta$

Where,

$F\to force\ applied\\\\S\to displacement\ caused\\\\\theta\to angle\ between\ F\ and\ S$

Now, the work done is maximum when both force and displacement is in same direction. ( $\theta=0^\circ$ )
Work done is minimum when both force and displacement are in opposite direction. ( $\theta=180^\circ$ )
Work done is zero when force and displacement are perpendicular to each other. ( $\theta=90^\circ$ )

Here, as the pumpkin is raised to a height 'h', there is force applied against gravity in the upward direction. So, force and displacement are in same direction and thus the angle is 0° between the force and displacement vectors.

So, work done is given as:

$W=Force\times Vertical\ displacement$

Force applied is equal to the gravitational force applied by the Earth but in the opposite direction.

So, Force = mg = $2.9\times 9.8 = 28.42\ N$

So, work, $W=Fy=28.42\times 1.5=42.63\ J$

So, work done in lifting the pumpkin is 42.63 J.

Now, when the pumpkin is carried to the check-out stand, the displacement is horizontal while the force applied is still in the upward direction.

So, the force and displacement are perpendicular to each other. Thus, the work done is zero.

4 0

4 years ago

4. A crane has a weight of 85000 N and it rests on two caterpillar tracks which have a total

vagabundo [1.1K]

Answer:

50kPa and if the area decreases, the pressure increases

Explanation:

P=F/A; P=pressure, F=force, A=area

85000N/1.7 m^2 = 50000 N/m^2; Pa = Pascal = N/m^2

=50 kPa

4 0

3 years ago