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joja [24]
3 years ago
6

What is incorrect in this? And how do I correct it?

Mathematics
1 answer:
german3 years ago
7 0

\bf \begin{cases} y=3x+2\\ -3x+y=2\\ 3x-y=-2\\ ------\\ 6x-2y=10 \end{cases}\implies  \begin{cases} 3x-y=-2\\ 6x-2y=10 \end{cases}\implies  \begin{bmatrix} 3&-1&|&-2\\ 6&-2&|&10 \end{bmatrix}\\\\ -------------------------------

\bf \stackrel{\textit{system's determinant}}{ \begin{bmatrix} 3&-1\\6&-2 \end{bmatrix}\implies (3\cdot -2)-(6\cdot -1)}\implies -6-(-6)\implies -6+6\implies 0 \\\\\\ \stackrel{\textit{systerm determinant of 0 means}}{\textit{the system has \underline{no solutions } or \underline{infinitely many solutions}}}

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Answer:

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3 years ago
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aalyn [17]
Hello!

To put -3x-7y-14=0 into standard form, or ax+by=c where the a value cannot be negative, and there are no fractions or decimals, or any common factors, first add -14 to both sides to get -3x-7y=14. Then, since your a value is negative, multiply the entire equation by -1 which will result in your answer:
3x+7y=-14

Hope this helps!
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