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3 years ago

What is incorrect in this? And how do I correct it?

Mathematics

1 answer:

german3 years ago

7 0

$\bf \begin{cases} y=3x+2\\ -3x+y=2\\ 3x-y=-2\\ ------\\ 6x-2y=10 \end{cases}\implies \begin{cases} 3x-y=-2\\ 6x-2y=10 \end{cases}\implies \begin{bmatrix} 3&-1&|&-2\\ 6&-2&|&10 \end{bmatrix}\\\\ -------------------------------$

$\bf \stackrel{\textit{system's determinant}}{ \begin{bmatrix} 3&-1\\6&-2 \end{bmatrix}\implies (3\cdot -2)-(6\cdot -1)}\implies -6-(-6)\implies -6+6\implies 0 \\\\\\ \stackrel{\textit{systerm determinant of 0 means}}{\textit{the system has \underline{no solutions } or \underline{infinitely many solutions}}}$

You might be interested in

Theo started to solve the quadratic equation (x + 2)^2 – 9 = –5. He added 9 to both sides and the resulting equation was (x + 2)

Sliva [168]

When we take the square root of each side, the equation would become:
abs (x+2) = 2
⇒ x+2 = <span>±2.

The final answer is </span><span>x + 2 = ±2.
</span>
Hope this helps~

6 0

4 years ago

Read 2 more answers

Item 3

Kruka [31]

Answer:

The given system as (3,3) as its solution.

Step-by-step explanation:

Here, the given system of the equation is:

4 x + 2 y = 18 ................ (1)

2 x + 3 y = 15 ............... (2)

Now, to use the elimination method, w need to eliminate any of the variable.

Eliminate the variable x in the given system.

Multiply equation (2) with -2 we get,

(2 x + 3 y = 15 )(-2) ⇒ -4x - 6y = -30 ....... (3)

Add (1) and (3), we get:

4 x + 2 y -4x - 6y = 18 -30

or, - 4 y = - 12

or, y = 12/4 = 3 ⇒ y = 3

Putting in (1), we get

4x + 2(3) = 18 or, 4x = 18 - 6 = 12

or, x = 3

(x,y) = (3,3)

Hence, the above system as (3,3) as its solution.

6 0

3 years ago

For reviewing purposes

sergeinik [125]

Answer:

(25-16)/9=

=9/9=1 because 5^2 is 25 and 3^2 is 9 (5x5)/(3x3)

5 0

3 years ago

1.A cube has side lengths of 15 inches, what is the surface area and volume of the cube? 2. A cube has side lengths of 8 inches,

omeli [17]

Answer:

Cube 1: 3375 cubed inches, 1350 inches squared.

Cube 2: 512 cubed inches, 384 inches squared.

Step-by-step explanation:

Formula for Volume of a Cube: $V=s^3\\$ (s - side length)

Formula for Surface Area of a Cube: $SA=6s^2$ (s- side length)

The side length's 15 inches.

Find the volume:

$V=15^3\\\rightarrow 15*15*15=3375\\\boxed {V=3375}$

The volume of cube one is 3375in³.

Find the surface area:

$SA=6(15)^2\\\rightarrow 15^2 = 225\\SA = 6 * 225\\\boxed {SA=1350}$

The surface area of cube 1 is 1350in².

The side length's 8 inches.

Find the volume:

$V=8^3\\\rightarrow 8*8*8= 512\\\boxed {V=512}$

The volume of cube two is 512in³.

Find the surface area:

$SA=6(8)^2\\\rightarrow 8^2=64\\SA=6*64\\\boxed {SA=384}$

The surface area of cube 2 is 384in².

<em>Brainilest Appreciated. </em>

3 0

3 years ago

Write an expression for the sequence of operations described below.

den301095 [7]

Answer:

We conclude that:

''add 3 and the sum of 9 and v'' is algebraically represented by the expression as:

3 + 9 + v

Step-by-step explanation:

Given the statement

''add 3 and the sum of 9 and v''

Let us break down the statement

Let the number be: v

The sum of 9 and v: 9+v

Adding 3 and the sum of 9 and v will be: 3 + 9 + v

Therefore, we conclude that:

''add 3 and the sum of 9 and v'' is algebraically represented by the expression as:

3 + 9 + v

3 0

3 years ago