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Dennis_Churaev [7]
3 years ago
13

Analyze the graph of the exponential decay function. The initial value is.

Mathematics
1 answer:
Alexeev081 [22]3 years ago
7 0

The initial value is equal to x. It is also known as the number out front of the parenthesis.

A=x(1-r)^t

^t means raised to the t(time)

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If 7x+2a=3x+5a then x is equivalent to what
solniwko [45]

7x+2a=3x+5a

7x-3x = 5a -2a

4x = 3a

x = 3a/4

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3 years ago
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I need help on this question
Alenkinab [10]
Answer : I’ll say it’s B.
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QUESTION 9<br> Write the expression by using exponents.<br> 2.2.2.2.2.2<br> moginio<br> QUESTION 10.
lozanna [386]

Answer:

2^6

Step-by-step explanation:

2*2*2*2*2*2

There are six 2's multiplied together so the base is 2 and the exponent is 6

2^6

3 0
3 years ago
What is the 5-digit code?
kvv77 [185]

9514 1404 393

Answer:

  4 2 6 1 7 or 1 2 4 3 7

Step-by-step explanation:

4 are correct of 1,3,4,6,7

3 are correct of 0,2,3,6,7

1 is correct of 0,3,6,8,7 -- so not both 3 and 6, meaning 1, 4, 7 are correct

Correct digits so far are 1, 4, 7 and one of {3, 6}. Line 2 tells another is 0 or 2; line 3 tells it is not 0. This adds 2 to the list of correct digits.

This makes the correct digits 1, 2, {3, 6}, 4, 7. We don't know whether the last digit is 3 or 6.

__

Looking at digits correctly placed, line 2 tells us the code is either ...

  _ 2 6 _ 7  or  _ 2 _ 3 7

Then line 1 fills in those blanks as ...

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Either of these codes agrees with all of the clues.

3 0
2 years ago
Si un triángulo tiene una hipotenusa de 15 cm y un cateto que mide 12 cm, ¿cual es la longitud del otro cateto?
BartSMP [9]

Answer:

   

9cm

Explicación:

El teorema de pitagoras nos dice que la hipotenusa al cuadrado es igual a la suma de los catetos al cuadrado:

c^{2} =a^{2} + b^{2}

Donde c es la hipotenusa y a  y b son los catetos.

Por lo cual, podemos reemplazar c por 15cm y a por 12cm :

15^{2} =12^{2} +b^{2}

Finalmente , debemos resolver la ecuación para b, así que b es igual a :

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Por lo tanto, la longitud del otro cateto es 9 cm

3 0
2 years ago
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