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Ne4ueva [31]
3 years ago
9

At what point do the increasing and decreasing parts of the graphs in Part A intersect?​

Mathematics
1 answer:
noname [10]3 years ago
5 0
(-1,3)
Not sure if it’s right but it should be
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A New cell phone cost $225. The accessories cost 13% of the cell phone price. What is the cost of the accessories?
Anvisha [2.4K]
$29.25 use a calculator, 225 - 13% = 195.75, 225 - 195.75 = 29.25
3 0
3 years ago
Arrange the following in descending order
nekit [7.7K]

Answer:

0, -3, -5, -8, -12

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Francine ran 3 1/2 laps around the circular track in the school gym. The track has a diameter of 1/2 miles. About how far does F
Juliette [100K]

Answer:

Francine run 5.495 miles

Step-by-step explanation:

Given :

Francine ran  3\frac{1}{2}  laps around the circular track in the school gym.

The track has a diameter of 1/2 miles.

To Find :  About how far does Francine run?

Solution :

First we need to calculate the perimeter of circular track :

Perimeter of circle :  2\pi r

Since we are given the diameter = 1/2 miles = 0.5 miles

So, Radius will be (Diameter/2) = 0.5/2 = 0.25 miles

So, The perimeter will be:

2\pi *0.25

0.5\pi

Since \pi =3.14

⇒0.5*3.14

⇒1.57

Thus the circular track is of 1.57 miles .

Since she ran   3\frac{1}{2}  = 7/2=3.5 laps

1 lap = 1.57 miles

So, 3.5 laps = 1.57*3.5 =5.495 miles .

Hence ,  Francine run 5.495 miles


6 0
3 years ago
What is the value of this expression? (−2)^5
dalvyx [7]

Answer:

-32

Step-by-step explanation:

=(-2)^5

=-2*-2*-2*-2*-2-2

-2*-2=4

-2*-2=4

-2

4*4=16

16*-2=-32

Hope this helps :) ❤❤❤

6 0
2 years ago
One large bubble separates into four small bubbles so that the total area of the small bubbles is equal to the area of the large
anzhelika [568]

Answer:

10 cm.

Step-by-step explanation:

We'll begin by calculating the area of the small bubble. This can be obtained as follow:

Radius (r) = 5 cm

Area (A) =?

Since the bubble is circular in nature, we shall use the formula for area of circle to determine the area of the bubble. This is illustrated below:

A = πr²

A = π × 5²

A = 25π cm²

Next, we shall determine the total area of the small bubbles. This can be obtained as follow:

Area of 1 bubble = 25π cm²

Therefore,

Area of 4 bubbles = 4 × 25π cm²

Area of 4 bubbles = 100π cm²

Finally, we shall determine the radius of the large bubble. This can be obtained as follow:

Area of large bubble = total area of small bubbles = 100π cm²

Radius (r) =?

A = πr²

100π = πr²

100 = r²

Take the square root of both side

r = √100

r = 10 cm

Thus, the radius of the large bubble is 10 cm

5 0
2 years ago
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