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3 years ago

PLEASE help with these math questions

Mathematics

1 answer:

kaheart [24]3 years ago

3 0

1. C
2. A
3. D
4. 62/25
5. 4/33

By the way it is not fair. posting 5 sums for just 7 points. :)

anyway, if it helped u
do click thx.

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PLEASEEEE HELP ME

AURORKA [14]

Answer:

1- BE

2- CF

3 - AD

4 - B

5 -

6 - A

7- S

8- D

9- CDF / BDE

10 - C B A

11 - D

12 -DC / DF

7 0

3 years ago

If a bus travels 20 km in 30 minutes. What is the average speed of the bus?

sattari [20]

<span>So we need to find the average speed of the bus that travels 20 km in 30 minutes. Average speed is defined as: Average speed=distance travelled/time taken or: v=s/t. We know s=20 km and t=30 minutes=0.5h. So after we input our numbers in the equation, we get: v=20km/0.5h=40km/h. So the correct answer is C) 40km/h.</span>

4 0

2 years ago

Read 2 more answers

The following 5 questions are based on this information: An economist claims that average weekly food expenditure of households

liq [111]

Answer:

Null hypothesis: $\mu_{1}-\mu_{0}\leq 0$

Alternative hypothesis: $\mu_{1}-\mu_{2}>0$

$SE=\sqrt{\frac{12.5^2}{35}+\frac{9.25^2}{30}}=2.705$

b) 2.70

$t=\frac{(164-159)-0}{\sqrt{\frac{12.5^2}{35}+\frac{9.25^2}{30}}}=1.850$

b. 1.85

$p_v =P(Z>1.85)=0.032$

b. 0.03

a. We can reject H(0) in favor of H(a)

Step-by-step explanation:

Data given and notation

$\bar X_{1}=164$ represent the mean for the sample 1

$\bar X_{2}=159$ represent the mean for the sample 2

$\sigma_{1}=12.5$ represent the population standard deviation for the sample 1

$s_{2}=9.25$ represent the population standard deviation for the sample B2

$n_{1}=35$ sample size selected 1

$n_{2}=30$ sample size selected 2

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the expenditure of households in City 1 is more than that of households in City 2, the system of hypothesis would be:

Null hypothesis: $\mu_{1}-\mu_{0}\leq 0$

Alternative hypothesis: $\mu_{1}-\mu_{2}>0$

We know the population deviations, so for this case is better apply a z test to compare means, and the statistic is given by:

$z=\frac{(\bar X_{1}-\bar X_{2})-0}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other".

Standard error

The standard error on this case is given by:

$SE=\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}$

Replacing the values that we have we got:

$SE=\sqrt{\frac{12.5^2}{35}+\frac{9.25^2}{30}}=2.705$

b. 2.70

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{(164-159)-0}{\sqrt{\frac{12.5^2}{35}+\frac{9.25^2}{30}}}=1.850$

P-value

Since is a one side right tailed test the p value would be:

$p_v =P(Z>1.85)=0.032$

b. 0.03

Conclusion

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis.

a. We can reject H(0) in favor of H(a)

4 0

2 years ago

What is N in -2n+2(3n+14)=-20

seraphim [82]

Answer:

To solve for n you need to get it by itself

First you want to distribute your 2 through the (3n+14)

-2n+6n+28=-20 (2*3n+2*14= 6n+28)

Now you want to combine any like terms if possible

4n+28=-20 (-2n+6n=4n, both like terms)

Then you want to subtract -28 from both sides

4n=-48 (28-28=0, -20-28=-48)

Lastly you want to divide both sides by 4

n=-12 (4n/4=n, -48/4= -12)

4 0

3 years ago

Consider a sequence given by the formula f(n)=3n-1 starting with n=1. Generate the first 5 terms of the sequence

Rufina [12.5K]

Answer:

The first 5 terms are 2, 5, 8, 11, 14.

Step-by-step explanation:

You use the formula to find out each term.
f(n)=3n-1 starting with n=1. If n=1 that is the 1st term, if n=2 that is the 2nd term, and so on. n means what number term it is.
Now to find each term:

n=1: f(1)= 3(1)-1= 3-1= 2 The 1st term is 2
n=2: f(2)= 3(2)-1= 6-1= 5 The 2nd term is 5
n=3: f(3)= 3(3)-1= 9-1=8 The 3rd term is 8
n=4: f(4)= 4(3)-1= 12-1= 11 The 4th term is 11
n=5: f(5)= 5(3)-1= 15-1= 14 The 5th term is 14

So the first 5 terms are 2,5,8,11,14

5 0

2 years ago