Answer:
- equation: d(h) = 0.25|h -1600| -400
- depth is 250 ft at 1000 ft and 2200 ft from the west edge
Step-by-step explanation:
The crater shape can be modeled by an absolute value function with a slope of 0.25. The vertex of the function will not be at (0, 0) but will be at (1600, -400). The usual methods of translating functions apply. Horizontal displacement of the vertex is subtracted from the independent variable; vertical displacement is added to the function value.
d(h) = 0.25×|h -1600| -400
We know the horizontal displacement is 1600 ft, because the depth changes at a rate of 1/4 foot for each horizontal foot. A depth change of 400 feet will require 1600 horizontal feet to accomplish.
__
At a depth of 250 ft, the distance from the west edge can be found from ...
-250 = 0.25|h -1600| -400
150 = 0.25|h -1600| . . . . . . . . add 400
600 = |h -1600| . . . . . . . . . . . multiply by 4
This resolves to two equations:
- -600 = h -1600 ⇒ h = 1000
- 600 = h -1600 ⇒ h = 2200
The depth is 250 ft at distances of 1000 ft and 2200 ft from the west edge.
_____
<em>Comment on the equation</em>
We have chosen to make depths be negative numbers. If you want the equation to give positive numbers for depth, multiply it by -1:
d = 400 -0.25×|h -1600|
The answer is 3n-4 because 4 is being subtracted
Answer:
Step-by-step explanation:
Probability of good given properly adjusted P(G/P) = .5
Probability of bad given properly adjusted P(B/P) = .5
Probability of inappropriately adjusted P(I ) = .1
Probability of properly adjusted P(P) = .4
Probability of good given inappropriately adjusted P( G/I ) = .25
Probability of bad given inappropriately adjusted P(B/I ) = .75
P( G ) = P(G/P) x P(P) + P( G/I ) x P(I )
P(P/G) = P(G/P) x P(P) / P(G/P) x P(P) + P( G/I ) x P(I )
= .5 x .4 / .5 x .4 + .25 x .1
= .20 / .20 + .025
.20 / .225
20 / 22.5
= 4 / 4.5 .
= 8 / 9 .
Answer K= 20/x
Step-by-step explanation:
Answer:
112°
Step-by-step explanation:
to be supplementary angles must equal 180°
so to solve just subtract 68° from 180° which equals 112°