1.Write the slope-intercept form of the equation of the line that is parallel to AB and passes through Point X. Show all work fo
r full credit.
2.Write the slope-intercept form of the equation of the line that is perpendicular to AB and passes through Point X. Show all work for full credit.
2.Write the slope-intercept form of the equation of the line that is perpendicular to AB and passes through Point X. Show all work for full credit.
2 answers:
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Answer:
The wire is approximately 42feet long
Step-by-step explanation:
We can mentally sketch out the shape that is formed between the guy wire and the antenna tower. This is simply a right-angled triangle with the opposite side being the height of the antenna (30 feet). The adjacent side is the distance on the ground between the point where the wire was fastened and the base of the antenna.
The hypotenuse side is the length of the wire we are looking for.
Parameters are given as:
Opposite : 30ft
Adjacent: 30ft
Hypotenuse: x feet
The hypotenuse =
Hypotenuse =
i. Domain and Range
The given function is
The domain of this function is,
The range refers to the y-values for which x is defined. x is defined for all values of y.
The range is all real numbers. See graph
ii. x-and-y-intercept
For x- intercept intercept we put
This implies that;
This will give us
The x-intercepts are
For y-intercept, we put
to obtain;
The y-intercept is
iii. Horizontal asyptote
Since degree of the numerator and the denominator are the same, there is a horizontal asymptote
To find the horizontal asymptote.
We divide the leading coefficient of the numerator by the leading coefficient of the denominator.
The horizontal asymptote is
iv. Vertical asymptote
To find the vertical asymptote, we equate the denominator to zero to get;
This implies that;
Split the middle term
Factor
Factor further
The vertical asymptotes are
