Two Characteristics of Gas state

The Ksp equation Ksp = [Ag+]2[CO32-] is the solubility product constant for which reaction?

DanielleElmas [232]

The solubility product is calculated using the ions that are formed by the dissolution of a solid. Therefore, the reaction for this solubility product expression is:
Ag₂CO₃ → 2Ag⁺ + CO₃⁻²

8 0

3 years ago

Solid lithium hydroxide is used to "scrub" CO2 from the air inspacecraft and submarines; it reacts with the CO2 to produce lithi

ArbitrLikvidat [17]

Answer:

223 L

Explanation:

Step 1: Write the balanced equation.

2 LiOH + CO₂ = Li₂CO₃ + H₂O

Step 2: Calculate the moles corresponding to 440 g of LiOH

The molar mass of LiOH is 23.95 g/mol.

440 g × (1 mol/23.95 g) = 18.4 mol

Step 3: Calculate the moles of CO₂ that react with 18.4 moles of LiOH

The molar ratio of LiOH to CO₂ is 2:1. The reacting moles of CO₂ are 1/2 × 18.4 mol = 9.20 mol.

Step 4: Convert 20°C to Kelvin

K = °C + 273.15 = 20 + 273.15 = 293 K

Step 5: Convert 753 torr to atm

753 torr × (1 atm/760 torr) = 0.991 atm

Step 6: Calculate the volume of CO₂

We will use the ideal gas equation.

P × V = n × R × T

V = n × R × T / P

V = 9.20 mol × (0.0821 atm.L/mol.K) × 293 K / 0.991 atm

V = 223 L

7 0

3 years ago

The freezing point of water H2O is 0.00°C at 1 atmosphere. A nonvolatile, nonelectrolyte that dissolves in water is urea. If 13.

Trava [24]

Answer:

Molality = 1.46 molal

The freezing point of the solution = -2.72 °C

Explanation:

Step 1: Data given

The freezing point of water H2O is 0.00°C at 1 atmosphere

urea = nonelectrolyte = van't Hoff factor = 1

Mass urea = 13.40 grams

Molar mass urea = 60.1 g/mol

Mass of water = 153.2 grams

Molar mass H2O = 18.02 g/mol

Kf = 1.86 °C/m

Step 2: Calculate moles urea

Moles urea = mass urea /molar mass urea

Moles urea = 13.40 grams / 60.1 g/mol

Moles urea = 0.223 moles

Step 3: Calculate the molality

Molality = moles urea / mass water

Molality = 0.223 moles / 0.1532 kg

Molality = 1.46 molal

Step 4: Calculate the freezing point of the solution

ΔT = i * Kf * m

ΔT = 1* 1.86 °C/m * 1.46 m

ΔT = 2.72 °C

The freezing point = -2.72 °C

3 0

3 years ago

There’s a part two for this but I can’t fit it all in this image, if you know how to do this please help me out. I’m stuck on th

Alina [70]

Answer:

See explanation

Explanation:

According to the law of conservation of mass; the total mass of reactants on the left hand side of the reaction equation is equal to the total mass of products on the right hand side of the reaction equation.

Hence, the total mass of each atom on either side of the reaction equation should be exactly the same.

Since there are two atoms of oxygen on the reactants side, the total mass of oxygen = 16 amu * 2 = 32 amu

Since there are two oxygen atoms on the products side, total mass of oxygen = 16 amu * 2 = 32 amu

8 0

3 years ago

for the following reaction: 1 CuO + 1 H2 --> 1 Cu +1H2O, what is the quantity of moles of H2O when there are 240 grams of CuO

Ber [7]

Considering the reaction stoichiometry, the quantity of moles of H₂O produced is 3.02 moles.

The balanced reaction is:

CuO + H₂ → Cu + H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

CuO= 1 mole
H₂= 1 mole
Cu= 1 mole
H₂O= 1 mole

The molar mass of the compounds present in the reaction is:

CuO= 79.55 g/mole
H₂= 2 g/mole
Cu= 63.55 g/mole
H₂O: 18 g/mole

Then, by reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of mass of each compound participate in the reaction:

CuO= 1 mole× 79.55 g/mole= 79.55 grams
H₂= 1 mole× 2 g/mole= 2 grams
Cu= 1 mole× 63.55 g/mole= 63.55 grams
H₂O: 1 mole× 18 g/mole= 18 grams

Then, it is possible to determine the moles of H₂O necessary by the following rule of three: If by reaction stoichiometry 79.55 grams of CuO produces 1 mole of H₂O, 240 grams of CuO produces how many moles of H₂O?

$molesofH_{2} O=\frac{240 grams of CuOx 1 mole ofH_{2} O }{79.55 grams of CuO}$

moles of H₂O= 3.02 moles

Finally, the quantity of moles of H₂O produced is 3.02 moles.

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6 0

3 years ago

Two Characteristics of Gas state​

Two Characteristics of Gas state