The answer is b) the gas particles have no attractive forces between them
Neutrons have a neutral charge. =>
Answer:
Theoretical value is the value a scientist expects from an equation, assuming perfect or near-perfect conditions. Experimental value, on the other hand, is what is actually measured from an experiment. Rarely (in fact never) are these numbers the same.
Take the area of a sheet of paper. I know that the area of a rectangle can be found by multiplying the lengths of both sides together. I can assume an 8.5x11 sheet, so I calculate exactly 93.5 square inches. This is my theoretical value. When I actually do the measurements on my paper, it turns out my paper has been slightly cut on one end, or I’m measuring with a shoddy ruler. Therefore, I might measure only 92.8 square inches. This is my experimental value. See thats it’s close, but not exact.
Expanding on this concept, quantum mechanics is so widely accepted in the scientific community because many theoretical values calculated by mathmaticians concurred with experimental values to many, many decimal places. These would be constants such as Plank’s Constant, energy levels of harmonic potentials, and energy levels of the hydrogen atom.
Explanation:
Answer:
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<em>a) Balanced chemical equation:</em>
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<em>b) Theoretical yield:</em>
c) % yield:
Explanation:
The complete question is:
<em>In a particular reaction 6.80g of dinitrogen trioxide gas (N₂0₃) was actually produced by reacting 8.75g of oxygen gas (O₂) with excess nitrogen gas (N₂)</em>
<em>a) Write a balanced chemical equation for the reaction. Be sure to include physical states in the equation.</em>
<em>b) Calculate the theoretical yield (in grams) of dinitrogen trioxide: Use dimensional analysis</em>
<em>c) Calculate the % yield of the product</em>
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<h2>Solution</h2>
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<em>a) Write a balanced chemical equation for the reaction. Be sure to include physical states in the equation.</em>
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Check the balance:
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Atom Left-handside Right-hand side
N 2×2=4 2×2=4
O 3×2=6 2×3=6
- Mole ratio: it is the ratio of the coefficients of the balanced equation
<em>b) Calculate the theoretical yield (in grams) of dinitrogen trioxide: Use dimensional analysis</em>
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<u>1. Convert 8.75 g of O₂(g) to number of moles</u>
- number of moles = mass in grams / molar mass
- molar mass of O₂ = 15.999g/mol
- number of moles = 8.75g / 15.999 g/mol = 0.5469 mol O₂
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<u>2. Use dimensional analysis to calculate the maximum number of moles of N₂O₃(g) that can be produced</u>
<u>3. Convert to mass in grams</u>
- mass = number of moles × molar mass
- molar mass of N₂O3 = 76.01g/mol
- mass = 0.3646mol × 76.01g/mol = 27.7g N₂O3
<em>c) Calculate the % yield of the product</em>
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Formula:
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- %yield = (actual yield/theoretical yield)×100
Substitute and compute:
- % yield = (6.80g/27.7g)×100 = 24.5%
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Explanation:
hope the picture above help u understand:)