Just simply subtract 23 by 15 to get the difference of 8
Answer:
Domain: (-∞, 4]
Range: [0, ∞)
General Formulas and Concepts:
<u>Algebra I</u>
- Domain is the set of x-values that can be inputted into function f(x)
- Range is the set of y-values that are outputted by function f(x)
Step-by-step explanation:
According to the graph, we see the line's x-value span from negative infinity to 4. Since 4 is closed dot, it is inclusive in the domain:
(-∞, 4] or x ≤ 4
According to the graph, we see the line's y-value span from 0 to infinity. Since 0 is closed dot, it is inclusive in the range:
[0, ∞) or y ≥ 0
It is 1/6 or .16 I used Photomath
Step-by-step explanation:
We are asked to simply (2√5 + 3√2)². Using formula: (a + b)² = a² + b² + 2ab. Let's say 2√5 = a, 3√2 = b. So,
→ (a + b)² = a² + b² + 2ab
→ (2√5 + 3√2)² = (2√5)² + (3√2)² + 2(2√5)(3√2)
We are aware about the fact that root means 1/2 and square of root means 2/2 that is 1. Using this we get:
→ (2√5 + 3√2)² = 4(5) + 9(2) + 2(2√5)(3√2)
Solve the brackets, to do so first put the like terms in one box.
→ (2√5 + 3√2)² = 4(5) + 9(2) + 2(2*3)(√5)(√2)
Solve the rest calculations.
→ (2√5 + 3√2)² = 20 + 18 + 2(6)(√10)
→ (2√5 + 3√2)² = 38 + 12√10
Option (a) (38 + 12√10) is the correct option.
Answer:
y = -1/2x + 2
Step-by-step explanation:
y = 2x - 3. The slope here is 2. A perpendicular line will have a negative reciprocal slope. To find the negative reciprocal, just flip the slope and change the sign.
slope = 2 or 2/1.....flip it.....1/2....change the sign...-1/2. So our perpendicular line will have a slope of -1/2.
y = mx + b
slope(m) = - 1/2
(2,1)....x = 2 and y = 1
now we sub and find b, the y intercept
1 = -1/2(2) + b
1 = -1 + b
1 + 1 = b
2 = b
so ur equation is : y = -1/2x + 2 <===
and u can check it with ur points....(2,1)
y = 2x - 3
1 = 2(2) - 3
1 = 4 - 3
1 = 1 (yep...it checks out)
