1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kati45 [8]
3 years ago
13

What is the difference of 15 and 23=

Mathematics
2 answers:
Evgesh-ka [11]3 years ago
4 0
Just simply subtract 23 by 15 to get the difference of 8

Artyom0805 [142]3 years ago
4 0
23-15=8 and to make sure thats currect 15+8=23
You might be interested in
What is the value of the following expression 1.8 + 0.5(y + 6) - 2 t the power of 3 when y = 14?
aalyn [17]

Answer: The answer should be 38.

I also saw that you placed a t after the -2 so I wasn't sure if it was a mistake or if it was on purpose or you left another t out of the problem on accident.

Step-by-step explanation:

2.3   (14+6)   -2 to the power of three

2.3    (20)     -2 to the power of three

2.3     (20)     -8

    46-8

      38

I really hoped this helped and if I got it wrong with the t just reply to me c:

4 0
3 years ago
Enter the rate of change of the table below
poizon [28]
The rate of change is 23
4 0
2 years ago
Need help asap! Show work if you can, it’s completely ok if you don’t tho
Savatey [412]
Its A) -67
plug the m and n values into the function and solve using pemdas.
5(-7)-2(-7+3)^2
-35-2(-4)^2
-35-2(16)
-35-32
-67
8 0
3 years ago
Which is a graph of the equation y = 2x- 4
algol13
The first one because the slope is 2/1 and y-intercept is -4
7 0
3 years ago
Read 2 more answers
In a population of 10,000, there are 5000 nonsmokers, 2500 smokers of one pack or less per day, and 2500 smokers of more than on
Kazeer [188]

Answer:

In one month, we will have 4,950 non-smokers, 2,650 smokers of one pack and 2,400 smokers of more than one pack.

In two months, we will have 4,912 non-smokers, 2,756 smokers of one pack and 2,332 smokers of more than one pack.

In a year, we will have 4,793 non-smokers, 3,005 smokers of one pack and 2,202 smokers of more than one pack.

Step-by-step explanation:

We have to write the transition matrix M for the population.

We have three states (nonsmokers, smokers of one pack and smokers of more than one pack), so we will have a 3x3 transition matrix.

We can write the transition matrix, in which the rows are the actual state and the columns are the future state.

- There is an 8% probability that a nonsmoker will begin smoking a pack or less per day, and a 2% probability that a nonsmoker will begin smoking more than a pack per day. <em>Then, the probability of staying in the same state is 90%.</em>

-  For smokers who smoke a pack or less per day, there is a 10% probability of quitting and a 10% probability of increasing to more than a pack per day. <em>Then, the probability of staying in the same state is 80%.</em>

- For smokers who smoke more than a pack per day, there is an 8% probability of quitting and a 10% probability of dropping to a pack or less per day. <em>Then, the probability of staying in the same state is 82%.</em>

<em />

The transition matrix becomes:

\begin{vmatrix} &NS&P1&PM\\NS&  0.90&0.08&0.02 \\  P1&0.10&0.80 &0.10 \\  PM& 0.08 &0.10&0.82 \end{vmatrix}

The actual state matrix is

\left[\begin{array}{ccc}5,000&2,500&2,500\end{array}\right]

We can calculate the next month state by multupling the actual state matrix and the transition matrix:

\left[\begin{array}{ccc}5000&2500&2500\end{array}\right] * \left[\begin{array}{ccc}0.90&0.08&0.02\\0.10&0.80 &0.10\\0.08 &0.10&0.82\end{array}\right] =\left[\begin{array}{ccc}4950&2650&2400\end{array}\right]

In one month, we will have 4,950 non-smokers, 2,650 smokers of one pack and 2,400 smokers of more than one pack.

To calculate the the state for the second month, we us the state of the first of the month and multiply it one time by the transition matrix:

\left[\begin{array}{ccc}4950&2650&2400\end{array}\right] * \left[\begin{array}{ccc}0.90&0.08&0.02\\0.10&0.80 &0.10\\0.08 &0.10&0.82\end{array}\right] =\left[\begin{array}{ccc}4912&2756&2332\end{array}\right]

In two months, we will have 4,912 non-smokers, 2,756 smokers of one pack and 2,332 smokers of more than one pack.

If we repeat this multiplication 12 times from the actual state (or 10 times from the two-months state), we will get the state a year from now:

\left( \left[\begin{array}{ccc}5000&2500&2500\end{array}\right] * \left[\begin{array}{ccc}0.90&0.08&0.02\\0.10&0.80 &0.10\\0.08 &0.10&0.82\end{array}\right] \right)^{12} =\left[\begin{array}{ccc}4792.63&3005.44&2201.93\end{array}\right]

In a year, we will have 4,793 non-smokers, 3,005 smokers of one pack and 2,202 smokers of more than one pack.

3 0
3 years ago
Other questions:
  • Which two grids can be combined to represent 140%?
    14·2 answers
  • The absolute value of 18
    11·1 answer
  • Larissa asked 40 students to name their favorite food. 10 students said their favorite food was pizza. What percent of the stude
    8·2 answers
  • A sailboat is flooding 24.7 feet above sea level a dolphin swims buy at a depth of 13.1 feet what is the distance between the to
    5·1 answer
  • Joanna uses the function p = (n) = 30n − 450 to calculate the profit, p, in dollars that she makes from selling n cakes in her s
    8·1 answer
  • Can yall help me please
    11·1 answer
  • PLEASE HELP THIS QUESTION IS SO ANNOYING!!
    7·2 answers
  • Instructions: Find the measurement of the diagonal indicated in the following parallelogram.
    5·1 answer
  • Can someone help? Please
    10·1 answer
  • Take $27.99 from $42.79.
    12·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!