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2 years ago

10

What is the area of the polygon below

1 answer:

kvasek [131]2 years ago

5 0

The area is 84.

What I do it cut the polygon into something easier like a square and rectangle.

Rectangle: 6•12=72
Square: 4•3=12

Add them together and you have 84

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The inequality below represents h, the number of hours Ellie need to work this week to earn at least $360 by the end of the mont

Gnom [1K]

Answer:

The answer to your question is 10 hours.

Step-by-step explanation:

Inequality 12h + 240 > 360

Solve the inequality as if it was an equation

12h > 360 - 240

12h > 120

h > 120 / 12

h = 10 hours

Let's evaluate some number of hours

If h = 3 12(3) + 240 > 360

36 + 240 > 360

276 > 360 Incorrect, she needs to work more

than 3 hours

If h = 5 12(5) + 240 > 360

60 + 240 > 360

300 > 360 Incorrect, she needs to work more

than 5 hours

If h = 7 12(7) + 240 > 360

84 + 240 > 360

324 > 360 Incorrect she needs to work more

than 7 hours

If h = 11 12(11) + 240 > 360

132 + 240 > 360

372 > 360 Correct, she needs to work at least

10 hours.

7 0

3 years ago

What is the value for f(x)= 3^2x+1 when x =1/2

Papessa [141]

Taking 2x is power of 3.

So it will be like 3^(2*1/2) + 1
You are replacing 'x' with 1/2
and the equation becomes 3^1+1
So, f(1/2) = 4
Answer is 4.

If its like
<span>3^(2x+1)
Then its like 3^[(2*1/2) +1]
It becomes 3^(1+1) = 3^2 = 9
So, the answer is 9
</span>

8 0

3 years ago

If g(x)= -(3/(4x)) , find g(g(x)) please show work.

ivann1987 [24]

Answer:

$g(g(x)) = x$

Step-by-step explanation:

$g(x) = -\dfrac{3}{4x}$

$g(g(x)) = -\dfrac{3}{4g(x)}$

$g(g(x)) = -\dfrac{3}{4(-\frac{3}{4x})}$

$g(g(x)) = -\dfrac{3}{4} \div (-\frac{3}{4x})$

$g(g(x)) = -\dfrac{3}{4} \times (-\frac{4x}{3})$

$g(g(x)) = \dfrac{3 \times 4x}{4 \times 3}$

$g(g(x)) = x$

4 0

2 years ago

Read 2 more answers

The illuminance of a surface varies inversely with the square of its distance from the light source. If the illuminance of a sur

lesya692 [45]

Answer: b) 6

Step-by-step explanation:

Given : The illuminance of a surface varies inversely with the square of its distance from the light source.

i.e. for d distance and l luminance , we have

$d^2\times l=k$ , where k is constant. (1)

If the illuminance of a surface is 120 lumens per square meter when its distance from a certain light source is 6 meters.

From (1), we have

$\Rightarrow (6)^2\times 120=k\\\\\Rightarrow\ k=4320$ (2)

For the distance (d) corresponds to the illuminance to 30 lumens per square meter , we have

$d^2\times 30=k$

Put value of k , we get

$d^2\times 30=4320\\\\\Rightarrow\ d^2=\dfrac{4320}{30}=144\\\\\Rightarrow\ d^2=144\\\\\Rightarrow\ d= 12$

Then , the number of meters should the distance of the surface from the source be increased= 12 meters- 6 meters = 6 meters.

3 0

3 years ago

Vikentia [17]

Answer:

Part a) The inequality that represent the situation is

$x+(3x)+(6x) \leq 350\ in$

Part b) The possible lengths of the shortest piece of wire are all positive real numbers less than or equal to $35\ inches$

Step-by-step explanation:

Let

x------> the length of the first wire

3x---> the length of the second wire

2(3x)=6x -----> the length of the third wire

Part a) WRITE AN *INEQUALITY* THAT MODELS THE SITUATION

we know that

The inequality that represent the situation is

$x+(3x)+(6x) \leq 350$

Part b) WHAT ARE THE POSSIBLE LENGTHS OF THE SHORTEST PIECE OF WIRE?

we know that

The shortest piece of wire is the first wire

so

Solve the inequality

$x+(3x)+(6x) \leq 350$

$10x \leq 350$

Divide by 10 both sides

$x \leq 35\ in$

The possible lengths of the shortest piece of wire are all positive real numbers less than or equal to $35\ inches$

4 0

2 years ago