Answer:
-2x + 3 – (5 – 6x) = 4x - 2
Step-by-step explanation:
The given expression is :
-2x + 3 – (5 – 6x)
We need to simplify the above expression. First opening the brackets.
-2x + 3 – (5 – 6x) = -2x + 3 – 5 + 6x
Taking like terms together,
= -2x+6x + 3 -5
= 4x - 2
So, the simplified expression is 4x - 2.
Answer:
The answer would be (1.23, 4.39)
Step-by-step explanation:
Because they are both equal to y, we can set the equations equal to each other and then solve.
4.9x - 1.64 = -0.25x + 4.7
5.15x - 1.64 = 4.7
5.15x = 6.34
x = 1.23
Now that we have the value for x, we can plug into either equation and find y.
y = -0.25x + 4.7
y = -0.25(1.23) + 4.7
y = -.31 + 4.7
y = 4.39
Answer:
39
Step-by-step explanation:

Answer:
5/8
explanation:
5/4(2)=10/8-5/8
Answer:
There is some mistake in the question, because the solutions are x = -1.445 and x = -34.555
Step-by-step explanation:
Given the functions:
f(x) = x² + 4x + 10
g(x) = -32x - 40
we want to find the points at which f(x) = g(x).
x² + 4x + 10 = -32x - 40
x² + 4x + 10 + 32x + 40 = 0
x² + 36x + 50 = 0
Using quadratic formula:






