II. f(x) doubles for each increase of 1 in the x values. Thus, r must be 2, and so we our ar^1 = 6 from ( I ) above becomes f(x) = a*2^x. Applying the restriction ar^1 = 6 results in f(1) = a*2^1 = 6, or a = 3.
Then f(x) = ar^x becomes f(x) = 3*2^2 (Answer A)
Move the -7 to the right, its sign will flip (do you know why?)
Negate both sides to change -x to x
-x = 16+7
-x = 23
x = -23
Answer:
for the second page the answer is B the third page is D
Step-by-step explanation:
- 24 + 25 (49 + 64 + 55)= 168
- Hope this helps
- i could only give you two of them
- Brainliest plz
- Ask questions if wrong
I think it is already reduced.
How you a doin?
Answer: B
Step-by-step explanation:
