<u>Answer:
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Required five terms of sequence are 19 , 12 , 5 , -2 and -9 .
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Solution:
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Need to find the five terms of the sequence.
Given recursive rule is f(x) = f(x-1) -7
Substituting x = 2 , f(2) = f(2-1)-7
= f(2) = f(1) – 7 ------(1)
Also given that f(2) = 12.
On substituting the given value of f(2) in eq (1) we get
12 = f(1) – 7
f(1) = 12 + 7 = 19
Using given recursive rule and given value of f(2) calculating f(3)
Substituting x = 3 ,
f(3) = f(3-1) – 7
= f(2) – 7
= 12 – 7
= 5
Using given recursive rule and calculated value of f(3) calculating f(4)
Substituting x = 4,
f(4) = f(4-1) – 7
= f(3) – 7
= 5– 7
= -2
Using given recursive rule and calculated value of f(4) calculating f(5)
Substituting x = 5,
f(5) = f(5-1) – 7
= f(4) – 7
= -2– 7
= -9
Hence required five terms of sequence are 19 , 12 , 5 , -2 and -9 .
Answer:
A
Step-by-step explanation:
write it as a ratio
11:6 = 110: x
cross multiply
11x= 660
divide by 11 on both sides
x= 60
Hey there!
Question #1.
2^6 + (2^3)^3
= 64 + (8)^3
= 64 + 8^3
= 64 + 512
= 576
Therefore, the answer should be:
Option A. 576
Question #2.
11^-4 * 11^8
= 1/14,641 * 214,358,881
= 14,641
≈ 11^4
Therefore, the answer should be:
Option C. 11^4
Good luck on your assignment & enjoy your day!
~Amphitrite1040:)
8 > 7 +
Subtract 7 from both sides
1 >
Multiply both sides by 6
6 > x Flip it around so it's easier to read
x < 6
You can graph your answer by drawing an open circle at the 6 and coloring the line to the left. The circle should be open, because x is <em>less than 6</em>, not less than or equal to. You would color to the left to show that x can be anything less than 6.